slicing an M-by-N-by-3 matrix using an M-by-N matrix of logical values

8 vues (au cours des 30 derniers jours)
Hi everybody
I have an RGB image as a MxNx3 matrix.
I would like to slice it using an MxN matrix of logic values (one for each pixel) and add a 1x1x3 value to those pixels. I'm trying to a clean way to do it.
In other words, I'm trying to do something like this
A = rand(200,200,3);
i = rand(200,200) > 0.5;
C = cat(3,0.3,0.4,0.2);
A(i) = 0.5*A(i,:) + 0.5*C; %doesn't work!
The only ways I found is either "unpacking" each MxN submatrix to a new variable like this
R = A(:,:,1);
G = A(:,:,2);
B = A(:,:,3);
R(i) = 0.5*R(i) + 0.5*C(1);
G(i) = 0.5*G(i) + 0.5*C(2);
B(i) = 0.5*B(i) + 0.5*C(3);
Anyone got a better idea?

Réponse acceptée

Walter Roberson
Walter Roberson le 12 Avr 2018
A = A + repmat(i, [1, 1, 3]) .* repmat(C, [size(A,1), size(A,2), 1]);
Since R2016b this can be expressed as
A = A + i .* C;
  2 commentaires
Luca Amerio
Luca Amerio le 12 Avr 2018
The first one is nice, but the second one is great!
Nice one, thank you!
Walter Roberson
Walter Roberson le 12 Avr 2018
dpb's Answer takes into account the selective 1/2 where mine does not. The fix would be
A = A + (C - A)/2 *.i;

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Plus de réponses (1)

dpb
dpb le 12 Avr 2018
A=0.5*(A.*i+C.*i);
  1 commentaire
Walter Roberson
Walter Roberson le 12 Avr 2018
Note that this requires R2016b or later due to differences in the sizes of the objects.

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