calculating the difference between 2 dates

Dear all,
I would like to calculate the difference between the dates say,
20/11/08 and 12/10/2011 in weeks and in months
cheers

 Réponse acceptée

Walter Roberson
Walter Roberson le 25 Mai 2012
numdays = datenum('12/10/2011') - datenum('20/11/08');
numweeks = numdays / 7; %and round() or floor() or ceil() as appropriate
numdaysvec = datevec(numdays);
nummonths = numdaysvec(1) * 12 + numdaysvec(2) - 1;
Note that you might have to give datenum() a hint as to whether the first date is the 11th month of 2008 or the 8th month of 2011.
Also, I used a shortcut here of converting the day offset as if it was a date relative to "year 0". MATLAB has weak leap-year routines that believe that "year 0" was a leap year. More accurate would be to datevec() the original dates and do modular arithmetic.
Oh yes, you also need to decide whether dates in the same month count as "0 months" or as "1 month" for your purposes.

4 commentaires

antonet
antonet le 26 Mai 2012
Hi Waterson. I get the following message
numdays = datenum('12/10/2011') - datenum('20/11/08');
??? DATENUM failed.
Failed to parse date string.
Error using ==> datevec at 259
20 is too large to be a month.
Any suggestions?
Thanks
antonet
antonet le 26 Mai 2012
i think it should be
numdays = datenum({'02/11/08'},'dd/mm/yy') - datenum({'09/10/11'},'dd/mm/yy')
Walter Roberson
Walter Roberson le 26 Mai 2012
Your date '20/11/08' is ambiguous. MATLAB is guessing incorrectly about the format it is in. You should be telling MATLAB the format when you datenum() the string. http://www.mathworks.com/help/techdoc/matlab_prog/bspgcx2-1.html#bsplnu3-2
datenum('20/11/08', 'dd/yy/mm') or datenum('20/11/08', 'dd/mm/yy') as appropriate
antonet
antonet le 26 Mai 2012
Thank you!

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Plus de réponses (1)

Andy
Andy le 13 Mar 2018
Modifié(e) : Andy le 13 Mar 2018

1 vote

there's something better now since 2014 release I believe:
w = between(startRange,endRange,'weeks')
y = between(startRange,endRange,'years')
m = between(startRange,endRange,'months')

2 commentaires

Indeed:
>> between(datetime('20-Nov-2008'),datetime('12-Oct-2011'),{'weeks' 'months'})
ans =
calendarDuration
34mo 3w
Rosanna
Rosanna le 11 Oct 2018
Hi all I have to compute the occurrence time (days from the starting date) of a large number (eg N=1000) of events, for which I have the Year, Month, Day, Hour, Minute in numerical format (eg 2008, 05, 23, 08, 34). How can I proceed? Thanks Rosanna

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