Effacer les filtres
Effacer les filtres

Loop plus diff function with non-integers: Feasible?

2 vues (au cours des 30 derniers jours)
Charles Martineau
Charles Martineau le 31 Mai 2012
hi all,
I am not sure if this is easy or not but I am struggling with the following:
Say that I have a vector Xt (10,000*1) of daily stock returns. I built this partition function formula:
for j=1:125;
E=Xt(1:j:end);
EE=diff(E(2:end));
EEE=diff(E(1:end-1));
Sq(j)=sum(abs(EE-EEE).^3);
end;
where j=1:125 is the various intervals that I wish to calculate the difference EE-EEE from the vector Xt. Now, what is the most efficient way for me to calculate the EE-EEE using non integer numbers?
If I construct a new vector as follow:
expo=0:1000;
A=1.1*ones(size(expo));
ddt=A.^expo;
in ddt there are numbers in which I would like to implement rather than 1:125.
(ddt vector looks like [1 1.1 1.21 1.331 1.4641 1.61051 1.771561 1.9487 2.14358]
What's the best way for to achieve this? In my orignal formula, I generate a Sq vector of size 1X125 for integer intervals but I want more numbers therefore I must turn to non-integer numbers.
Thank you very much for the help!

Réponse acceptée

Oleg Komarov
Oleg Komarov le 31 Mai 2012
If I understood correctly, you want to partition non non integer ontervals. Say you want to select Xt every 1.331 step.
Since you have values only at Xt(1), Xt(2) etc... and not on Xt(1.331), Xt(2.662) etc but you still want to get those number then you can interpolate.
  2 commentaires
Charles Martineau
Charles Martineau le 31 Mai 2012
Yes exactly! Basically the best is for me to generate a new Xt vector with elements 1.331 2.662. ... and then take the diff of this vector.
Oleg Komarov
Oleg Komarov le 31 Mai 2012
Use interp1() to generate the interpolated values of Xt.

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Charles Martineau
Charles Martineau le 31 Mai 2012
If anyone can help... I am really struggling with this one!

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