How to shift graphs in Matlab?

Hello,

I am trying to figure out how to start my graph correctly. Time is starting at zero, however my statements are starting at 2 and just putting a zero for my first element, not 1,2. They should be starting from the same y-intercept and then vary after time equals 7.45ish. The first figure is without the correction, and the second image is if I try and fix the shift with changing line 114 with 1/10 - 1/10. If you can help me with this issue that will be great.

CODE:

close all

clear all, clc

g = 9.81; %acceleration due to gravity m/s^2

l = 20; % length of rope from top of platform

L = l+9;

h = 91-l; % the total displacement of the spring

d = l +h; % the height of the platform

m = 100; % mass in kg

k = 2*m*g*d/h^2; % spring constant

c =10; % damping constant

x0 =  -m*g/k; % position at time = 0, when the spring engages

v0 = sqrt(2*g*l); % velocity at time =0, when the spring engages

wn = sqrt(k/m); % omega_n, natural frequency, radians/sec

z = c/(2*m*wn); % zeta, damping ratio, 

wd = wn*sqrt(1-z^2); % damping frequency, radians/sec

A = sqrt(((v0+z*wn*x0)^2+(wd*x0)^2)/(wd)^2); % amplitude

phi = atan(wd*x0/(v0+z*wn*x0)); % phase angle

syms t

x = A.*exp(-z.*wn.*t).*sin(wd.*t+phi); % position function

v = diff(x,t); % velocity function

a = diff(v,t); % accleration function

j = diff(a,t); % jerk function

% x is maximum when velocity is zero

t_x_max = double(solve(v==0,t)); % solves for time when v is zero

t_x_max = t_x_max(t_x_max>=0); % selects the positive time values

t = t_x_max; 

x_max = double(subs(x)); % maximum displacement for time when v is zero

x_total = x_max+abs(x0) % x is measured from the equilibrium position. This adds

%the initial position to the displacement from the equilibrium postion. 

if x_total > h

      disp('Splat!')

else 

      disp('Jumper is safe')

end

% Velocity is maximum when acceleration is zero.

syms t

t_v_max = double(solve(a==0,t)); % time when a is zero. 

t_v_max = min(t_v_max); 

t = t_v_max;

v_max = double(subs(v)); % maximum velocity

% acceleration is maximum when  jerk is zero. 

syms t 

t_a_max = double(solve(j==0,t));

t_a_max = t_a_max(t_a_max >=0);

t = t_a_max;

a_max = double(subs(a)); % maximum acceleration

gs = abs(a_max/g) % accleration/acceleration due to gravity gives the number of gs. 

if gs > 2

      disp('Black out')

else

      disp('Jumper is awake')

end

Td = 2*pi/wd; % damped period

n = 0:20;

time = Td*n/2+t_x_max; % time at which x peaks occur

t = time;

x_peaks = double(subs(x)); % x peak values

for i = 1:1:numel(x_peaks)

      if abs(x_peaks(i))<4

          t_over = time(i);

          fprintf('Ride ends at %g \n', t_over)

          break

      end

end

% subplot(3,1,1)

% scatter(time,x_peaks)

% hold on

% plot(time,4) 

% axis([0 60 -60 60])

% syms t    

% subplot(3,1,2)    

% fplot(x)

% hold on

% fplot(4)

% axis([0 60 -60 60])

% subplot(3,1,3)
% fplot(v)

% axis([0 60 -60 60])

% hold off
t_x0 = vpasolve(x==x0, 8)

C = m*g*l/(.5*int(v^2,0,t_x0))
clc

syms t

free_fall = x0+v0.*t+1/2.*g.*t.^2;

ff_vel = diff(free_fall);

%X- True position

X = zeros(1,601);

for i = 1:1:601

      t = i/10;

if subs(x)>x0

      X(i) = subs(x);

else

      v0= subs(v);

end

if subs(free_fall)<x0

      X(i) = subs(free_fall);

else

      v0 = subs(ff_vel);

end

end

t= [0:.1:60];

plot(t,X,'R--')

hold on

fplot(x)

xlim([0 10])

hold off

% t_x0 = vpasolve(x==x0, 7)
% 

% t = t_x0

% v_x0 = subs(v)
% 

% x = free_fall;

% t_x0 = vpasolve(x==x0,

[Krishna Bindumadhavan]

"Time is starting at zero, however my statements are starting at 2 and just putting a zero for my first element, not 1,2. They should be starting from the same y-intercept and then vary after time equals 7.45ish."

^ Could you please elaborate this with respect to the code? I was not able to understand what you are trying to say here.

[Jan]

Inserting a blank line after each line of code decreases the readability. Please don't do this. Remember, that the outcommented sections are confusing in general, most of all, if you post code in the forum.