How do I repeat a for loop for all columns?

9 vues (au cours des 30 derniers jours)
Bianca Batista
Bianca Batista le 7 Mai 2018
Réponse apportée : Jan le 7 Mai 2018
I have a for loop that runs through all of my 1,000 rows. The next step is to get this code to run exactly the same way but for each of the 10,000 columns. I don't know if there is a simple way to do this--I tried adding "for j=1:n_trials" but that didn't seem to work. Any help is appreciated. Thanks!
n_steps = 1000 n_trials = 10,000 x_pos = zeros(n_steps,n_trials);
for i=2:n_steps
direction=rand;
if direction < 0.3
x_pos(i) = x_pos(i-1)+1;
elseif (0.3 < direction) && (direction < 0.5)
x_pos(i)=x_pos(i-1)-1;
else
x_pos(i)=x_pos(i-1);
end
end

Réponse acceptée

Akbar
Akbar le 7 Mai 2018
Modifié(e) : Akbar le 7 Mai 2018
Try this. You should use two arguments (i,j) i=row number. j=column number. And one more "for" Loop, for the columns.
n_steps = 1000;
n_trials = 10000;
x_pos = zeros(n_steps,n_trials);
for i=2:n_steps
for j = 1:n_trials
direction=rand;
if direction < 0.3
x_pos(i,j) = x_pos(i-1,j)+1;
elseif (0.3 < direction) && (direction < 0.5)
x_pos(i,j)=x_pos(i-1,j)-1;
else
x_pos(i,j)=x_pos(i-1,j);
end
end
end

Plus de réponses (1)

Jan
Jan le 7 Mai 2018
With a vectorized approach:
n_steps = 1000;
n_trials = 10000;
x_pos = zeros(n_steps, n_trials);
for k = 2:n_steps
direction = rand(1, n_trials);
step = zeros(1, n_trials);
step(direction <= 0.3) = 1;
step((0.3 < direction) && (direction < 0.5)) = -1;
x_pos(k, :) = x_pos(k-1, :) + step;
end
I've modified one condition from < 0.3 to <= 0.3, such that direction==0.3 is caught also.

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