Efficient operation on individual matrix rows

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Chris B
Chris B le 22 Mai 2018
Commenté : Chris B le 23 Mai 2018
Hello,
I'm searching for a way to apply the Jacobian function to each row of a matrix. Essentially I need to access each row of a matrix and apply a function. I could use a "for loop" which is quite slow:
for i=1:size(a,1)
tmp = jacobian(a(i,:),b);
result=cat(1,result,tmp);
end
I also found this solution:
function dNdv = matjacobian(N,v)
rz = arrayfun(@(ii)jacobian(N(ii,:),v),(1:numel(N(:,1))).','un',0);
dNdv = cat(1,rz{:});
end
The second solution is faster but I'm wondering if there is a more efficient way. Or even a way to apply the jacobian to a multi row matrix.
Thanks in advance,
Chris

Réponse acceptée

Stephen23
Stephen23 le 22 Mai 2018
Modifié(e) : Stephen23 le 22 Mai 2018
"I could use a "for loop" which is quite slow:"
The problem is not the for loop, but the fact that you expand the array result on each loop iteration. Expanding arrays is slow. Read this to know why:
Using a loop (with a properly preallocated output) will be faster than using arrayfun. You can simply preallocate the output array to be the correct size before the loop, and your code will be quite fast:
out = nan(...); % defined to be the final size!
for k = ...
...
out(k,...) = ...
end
the correct size to use for preallocation depends on a and b: I am sure that can figure that out.
  1 commentaire
Chris B
Chris B le 23 Mai 2018
Perfect, that worked. The for loop with preallocation is indeed faster. Thanks.

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