Effacer les filtres
Effacer les filtres

How to count black pixels block by block in an image I divided into 16x16 blocks?

3 vues (au cours des 30 derniers jours)
I'm trying to write some code that divides a binary image into 16x16 non overlapping blocks and then goes through each block and counts the number of black pixels in it, then if the count exceeds a certain threshold the edges of the block are changed to a different color on the original image.
So far I managed to divide my image into the 16by16 blocks, but I don't know how to go through each of these and get the data I need, so any help would be appreciated.
Here is the code I got so far:
clear all;
RGB=imread('test.jpg');
I=rgb2gray(RGB);
imshow(I);
kernel = [1 1 1;1 10 -1;-1 -1 -1];
filteredImage = imfilter(I, kernel, 'same');
imshow(filteredImage);
threshold = graythresh(filteredImage);
X=im2bw(filteredImage,threshold);
BlockImage = im2double(X);
[m,n] = size(BlockImage);
Blocks = cell(ceil(m/16), ceil(n/16));
counti = 0;
for i = 1:16:m-15
counti = counti + 1;
countj = 0;
for j = 1:16:n-15
countj = countj + 1;
Blocks{counti,countj} = BlockImage(i:i+15,j:j+15);
end
end

Réponse acceptée

monika shivhare
monika shivhare le 30 Mai 2018
Assuming that if count(number of black pixels in a block) exceeds a certain threshold, you want to change the edges of block to a different color in the original image. You can use the following code below the one you have created cell array "Blocks"
% suppose threshold value is th =150
% different color is white nc=[r g b]
th=150;
nc=[255 255 255];
[r,c]=size(Blocks);
for i=1:r
for j=1:c
%cb is no of black pixels
cb=nnz(Blocks{i,j}==0);
if(cb>th)
%putting edges to a different color nc
x=(i-1)*16+1;
for y=(j-1)*16+1:j*16
RGB(x,y,:)=nc;
end
x=i*16;
for y=(j-1)*16+1:j*16
RGB(x,y,:)=nc;
end
y=(j-1)*16+1;
for x=(i-1)*16+1:i*16
RGB(x,y,:)=nc;
end
y=j*16;
for x=(i-1)*16+1:i*16
RGB(x,y,:)=nc;
end
end
end
end

Plus de réponses (0)

Produits


Version

R2017a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by