Strange Cell Array error

Hello. I have a cell array in a uitable that I want to find the min of the columns 2,3,4,5 - and for each column, extract the z position from the file name that corresponds to that minimum.

   for h=1:4       %first column is filename, so start at 2
      h
      data(:,h+1)
      class(data) 
      c2=str2num(cell2mat(data(:,h+1)))   %Select column fwhmH=2 etc.    
      c2min=min(c2(:));
      c2idx=find(c2==c2min);
      text=cell2mat(file(c2idx));
      C = strsplit(text,'zPos_');
      class(C);
      C=cell2mat(C(2));
      D=strsplit(C,'.tif')
      data2=horzcat(data2,D(1)) 
   end
   set(handles.uitable2,'data',data2)

However, on the 3rd loop (h=3), for the following code

      h
      data(:,h+1)
      class(data) 
      c2=str2num(cell2mat(data(:,h+1)))   %Select column fwhmH=2 etc.

I get the following output and error

h =

            3.00

ans =

    3×1 cell array

      {'8317' }
      {'10974'}
      {'14623'}

ans =

      'cell'

Error using cat
Dimensions of matrices being concatenated are not consistent.

Error in cell2mat (line 83)
            m{n} = cat(1,c{:,n});

I can't understand why as on the 1st & 2nd loop that correctly works, the data is of the same type - i.e. cell array

[Dennis]

Your cell entries are strings. You get that error message because '8317' has 4 chars and your other 2 cell entries have 5.

c2 = cellfun(@str2double,data(:,h+1));

[Jason]

Thankyou

Answer 1

[Stephen23]

c2 = str2double(data(:,h+1))

[Jason]

Thanks

Answer 2

[Sayyed Ahmad]

try this codes

data={'8317';'10974';'14623'}
for i=1:3
  c2(i)=str2num(data{i})
end