What would be the way to use one 3D array as index for other 3D array?

2 vues (au cours des 30 derniers jours)
Hello, I have two 3D arrays a (3x5x4) and o (1x5x4). What I would like to achieve is to use o array as index for a. The struggle is when I use the function below it would take whole o array when creating new array x (1x5x4), maybe anyone has any idea. I thought about pagefun, but it works with only predefined functions.
a=rand(3,5,4)
o= cat(3,[2 5 1 2 4],[2 5 3 1 5],[2 2 2 4 4],[2 3 1 5 4])
x=a(2,o,:)

Réponse acceptée

Stephen23
Stephen23 le 4 Juil 2018
The simplest solution is to use a temporary variable:
>> tmp = a(2,:,:);
>> x = tmp(o)
Another option would be to convert the subscript indices into linear indices, but this is not so trivial.
  5 commentaires
Stephen23
Stephen23 le 4 Juil 2018
Modifié(e) : Stephen23 le 4 Juil 2018
@Mantas Vaitonis: convert the subscript indices into linear indices:
>> a = rand(3,5,4)
a =
ans(:,:,1) =
0.619297 0.782286 0.293458 0.489529 0.063580
0.727413 0.462825 0.712196 0.129529 0.010375
0.535980 0.625046 0.098377 0.589341 0.623387
ans(:,:,2) =
0.532375 0.927982 0.581526 0.094430 0.486161
0.931640 0.580941 0.182186 0.314561 0.209293
0.826359 0.040024 0.528289 0.704205 0.360965
ans(:,:,3) =
0.225279 0.708014 0.587027 0.020373 0.792127
0.573342 0.530581 0.896023 0.556469 0.471478
0.795015 0.122115 0.109518 0.890492 0.351620
ans(:,:,4) =
0.082299 0.173384 0.587164 0.179035 0.244157
0.527470 0.635292 0.400517 0.953553 0.631803
0.886819 0.880137 0.526968 0.197963 0.232092
>> o = cat(3,[2,5,1,2,4],[2,5,5,3,4],[3,5,4,2,4],[2,1,1,1,4]);
>> S = size(a);
>> [R,~,P] = ndgrid(2,1:S(2),1:S(3)); % 1st input 2 -> row.
>> x = a(sub2ind(S,R,o,P))
x =
ans(:,:,1) =
0.462825 0.010375 0.727413 0.462825 0.129529
ans(:,:,2) =
0.580941 0.209293 0.209293 0.182196 0.314561
ans(:,:,3) =
0.896023 0.471478 0.556469 0.530581 0.556469
ans(:,:,4) =
0.635292 0.527470 0.527470 0.527470 0.953553
Mantas Vaitonis
Mantas Vaitonis le 4 Juil 2018
Yes this is exactly what I need, thank you.

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Matrix Indexing dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by