undefined function or variable error in matlab simulink?

hi.i want to simulate ur10 kinematic(inverse and forward) but when I run I have these errors(screenshot which is attached). the function name or path are correct. i run the trajectory planning block and have all 6 Theta at the output.

9 commentaires

From the images it appears that the problem is caused by the function ur10_forward_kinematics(). Are you able to run this function in MATLAB?
when I run it there is this error:
not enough input argument but I define theta1,..,6 in simulink
i have another Simulink file for SCSRA robot thati is similar to mine and while i running the mfile of it there is the same error(not enough input argument) but when i run Simulink it works.
i want to attach Simulink file but i cant.how can i do it?
It is giving an error because You are not calling it right. Where are you defining theta1,...,6? Also, you need to call it like this
ur10_forward_kinematics(theta1, theta2, theta3, theta4, theta5, theta6)
Also, you can attack the Simulink file by compressing it into a zip file.
at Simulink in trajectory planning(it is shown in screenshot I sent)
I call it :
[X,Y,Z,T06] = ur10_forward_kinematic(Theta1,Theta2,Theta3,Theta4,Theta5,Theta6,d_1,d_4,d_5,d_6,a_2,a_3)
It will be easier to suggest a solution if you can attach the model files as zip file.
my Simulink file

Connectez-vous pour commenter.

 Réponse acceptée

Ameer Hamza
Ameer Hamza le 10 Août 2018
There are some typing mistakes in ur10_forward_kinematic(). For example in the input list the variable name is Theta2, whereas in the code you are using Theta_2. You need to use the same name in both places. Also on line 39, you are using p06 whereas the actual name is P06 remember the variable names are case sensitive.
The file ur10_inverse_kinematic() contains some more involved problems. For example, at the beginning of your code you are using Theta1, Theta2, ... Theta6 but their values are not defined. You are not giving their values as function input neither defining inside the function. MATLAB has no way of knowing what values to take when the function run.

Plus de réponses (0)

Catégories

En savoir plus sur Modeling dans Centre d'aide et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by