Function error | Error: Function definitions are not permitted at the prompt or in scripts.

2 vues (au cours des 30 derniers jours)
Gaia
Gaia le 18 Juin 2012
Hello everybody,
I'm a new member of this community. I'd appreciate your help for a problem that I'm having with a little, silly function whom I type the code here.
function [val_min, pos_min] = comparison1(Isole_mat,Elhierro_mat)
[r,c]=size(Isole_mat);
for i = 1:r
latP = Isole_mat(i,2);
lonP = Isole_mat(i,3);
diffLat = latP - Elhierro_mat(:,2);
diffLon = lonP - Elhierro_mat(:,3);
distanza(:,i) = diffLat.^2+diffLon.^2;
%[dmin, I] = min(distanza(:));
end
[val_min, pos_min] = min(distanza);
What's wrong with it? Why do I get always the error message | Error: Function definitions are not permitted at the prompt or in scripts.
I saved the function in a m.file within the same name...
Please, help me understand.
Thank you in advance!
  4 commentaires
Walter Roberson
Walter Roberson le 19 Juin 2012
Please check that in your comparison1.m file, that the only lines before the "function" line, are comment lines and blank lines.

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Réponses (2)

per isakson
per isakson le 19 Juin 2012
Do you have more than one m-file with the name, comparison1? Check with
which comparison1 -all
Is
function [val_min, pos_min] = comparison1(Isole_mat,Elhierro_mat)
.
the first line in the m-file? And is
end
.
the last line of the m-file? The "end", which match "function" is optional, but I think it makes the function easier to read.
The Code Analyzer box (or mlint-box) at the right top of the editor is it green or at least not red?
  1 commentaire
Gaia
Gaia le 19 Juin 2012
I have just one file named comparison1.
In the first line I have some comments lines and blank lines, and in the last lines there are the outputs values:
[val_min, pos_min] = min(distanza);
The box is orange, but this was a problem I already had; anyway it is due to the letter "c" in this statement:
[r,c]=size(Isole_mat);
because "the value assigned might never be used", and to the following line:
distanza(:,i) = diffLat.^2+diffLon.^2;
because "it might be growing inside a loop. Consider preallocating for speed."

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Gaia
Gaia le 19 Juin 2012
A silly silly mistake... I was trying to call the function in the wrong way, forgetting that the variables aren't general but local...
Thank you all for your kind help!

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