# could anyone help me how to reduce the circshift to half of it.

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Prabha Kumaresan on 16 Aug 2018
Commented: Prabha Kumaresan on 16 Aug 2018
By using circshift i am getting 12 times what can be done inorder to reduce 12 to 6(which means half of it). Could anyone please help me on this.
Stephen23 on 16 Aug 2018
@Prabha Kumaresan: this is clearly related to your earlier questions of the last two days. Rather than showing us broken code with no comments or help or explanation, it would actually make things a lots easier if you explained what you are trying to achieve. Forget about your code attempts, they don't help us and are possibly not a very good solution anyway. Show us a simple example, complete with input and output arrays, so that we can understand what you want to achieve.

Rik on 16 Aug 2018
A_master=1:12;
for k=1:2:numel(A_master)%[1 3 5 7 9 11] for 12, [1 3 5] for 6, etc
fprintf('\nPossibilities %02d:\n',k);
A=circshift(A_master,1-k,2);
B=0;
while ~isempty(A)
B=B+1;
if B>numel(A)
ind=1;
B=1;%reset B
else
ind=[1 (numel(A)-B+2):numel(A) ];
end
C=A(ind)
A(ind)=[];
end
end
Prabha Kumaresan on 16 Aug 2018
thanks.It works