Plotting a function over an interval

I am trying to plot a function in which one term is (2^(-1/a))*(1+x)^(1+1/a). When a is very small, for example a=10^-4 or even smaller, this term turns to NaN. How can I plot this function?

9 commentaires

Torsten
Torsten le 17 Août 2018
The best you can do is write your function as
(1+x).*((1+x)/2).^(1/a)
If the problem remains, (1+x)/2 is simply too large (or "a" is too small).
Best wishes
Torsten.
Ali Baig
Ali Baig le 17 Août 2018
Thank you. It works up to a=10^-6.
Pieter Hamming
Pieter Hamming le 17 Août 2018
Can you give a little more information about the goal of the plot? This sounds like an occasion where a (semi-)log plot would be suitable. This in turn could help in rewriting the equation
Ali Baig
Ali Baig le 17 Août 2018
@Pieter hamming, this is exact solution of a convection-diffusion equation. I calculated the numerical solution using Finite Element Method and the goal of the plot was to compare the two solutions.
Pieter Hamming
Pieter Hamming le 17 Août 2018
I was a bit unclear in my question, sorry. What I meant is more info about the variables involved: size, scale and such.
Is a a single value of 10^-6? Is it a set of points on an interval? If so, how many points and on what interval?
Assuming you want to plot (2^(-1/a))*(1+x)^(1+1/a) for one value of a and a range of x, what range of x do you need?
What do you want with the plot? Visually compare to a previous plot? In that case a log plot should suffice.
These kind of details help a lot in determining how we can help you best. In the future, consider adding them immediately to the question :)
Ali Baig
Ali Baig le 17 Août 2018
I plotted 6 different graphs. For each graph, ''a'' is constant, and its values are 10^-1, 10^-2,.., 10^-6. Variable ''x'' vary from 0 to 1, and 40 uniformly-spaced x values are used. And the purpose of the graphs is to visually compare the exact solution and the finite element solution.
Thank you for your suggestions.
Torsten
Torsten le 17 Août 2018
If x only varies from 0 to 1, you should be able to plot your graphs for whatever "a" you want with my suggestion.
Ali Baig
Ali Baig le 17 Août 2018
I am trying to plot for ''a'' up to 10^-6 and the simplification propsed by Hamming works up to this value.
Torsten
Torsten le 17 Août 2018
Modifié(e) : Torsten le 17 Août 2018
x=linspace(0,1,40);
a=1e-12;
y=(1+x).*((1+x)/2).^(1/a);
plot(x,y)
works for me.

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le 17 Août 2018

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