Effacer les filtres
Effacer les filtres

Alternative to "round" for accurate accumulation

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Mukund
Mukund le 28 Août 2018
Réponse apportée : Stephen23 le 28 Août 2018
I have a vector
A=[0.970, 0.486, 0.439, 0.0143, 0] % Ref vector from Algorithm-1
B=7 % Final sum expected from A
A1=A/sum(A) % Proportionate for sum==1
B1=round(A1*B)
B1=[4 2 2 0 0] %Sum is 8 (not 7)
The objective is to convert vector A into integer such that the sum is B=7. Is there any matlab function by which sum of 7 can be achieved. Or can you please suggest other way. Kindly note that A changes in every iteration.
  2 commentaires
madhan ravi
madhan ravi le 28 Août 2018
Can you elaborate? which has to be eight A1 or B or B1?
madhan ravi
madhan ravi le 28 Août 2018
Can you elaborate what you are trying to do and what you are trying to achieve?

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Stephen23
Stephen23 le 28 Août 2018
>> n = fzero(@(k)sum(round(A*k))-7,[0.01,100])
n = 3.4811
>> V = round(A*n)
V =
3 2 2 0 0
>> sum(V)
ans = 7

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