find the average of a vector with specific condition ?

1 vue (au cours des 30 derniers jours)
MUKESH KUMAR
MUKESH KUMAR le 4 Sep 2018
Commenté : MUKESH KUMAR le 4 Sep 2018
I had A vector
A=[1 0 0 2 3 2 3 5 0 0 0 0 1 2 1 0 0 0 0 3 4 0 0 0 0 0 0 1 2 3 2 0 0 0 0 2 0 0]
like this. Now I want a vector B having average of corresponding non-zero value, like
B(1)=average(A(1));
B(4)=average(A(4):A(8));
B(13)=average(A(13):A(15);
B(20)=average(A(20):A(21));
B(28)=average(A(28):A(31)) and so on .....rest values should be zeros.
hence
B=[1 0 0 3 0 0 0 0 0 0 0 0 1.33 0 0 0 0 0 0 3.5 0 0 0 0 0 0 0 2 0 0 0 0 0 0 0 2 0 0 ]
  5 commentaires
MUKESH KUMAR
MUKESH KUMAR le 4 Sep 2018
So how can i take average of continuous values at starting point of each continuous group values and rest are zeros.
jonas
jonas le 4 Sep 2018
I'll give it a try in an hour if no one gave you an answer. This one is not as straight-forward as your previous questions, at least to me.

Connectez-vous pour commenter.

Réponse acceptée

jonas
jonas le 4 Sep 2018
Modifié(e) : jonas le 4 Sep 2018
Credits to Guillaume for cleaning up my original code.
A=[1 0 0 2 3 2 3 5 0 0 0 0 1 2 1 0 0 0 0 3 4 0 0 0 0 0 0 1 2 3 2 0 0 0 0 2 0 0];
B=zeros(size(A));
bounds = find(diff([0, A, 0] ~= 0));
starts = bounds(1:2:end);
ends = bounds(2:2:end) - 1;
B(starts) = arrayfun(@(s, e) mean(A(s:e)), starts, ends);
  4 commentaires
jonas
jonas le 4 Sep 2018
@Guillaume: Thank you sir, I'll update the code.
@Mukesh: The code should work now. There was a minor error in my original post. You were too quick to grab it :)
MUKESH KUMAR
MUKESH KUMAR le 4 Sep 2018
thanks for your support :)

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Data Types dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by