How many times each element of an array have the 1 value after n times assigned different logical values?
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Thao Linh Tran
le 21 Sep 2018
Commenté : Thao Linh Tran
le 21 Sep 2018
I have n same size matrices containing different logical values such as A1, A2, A3 matrices. It also can be considered that a matrix_A was assigned n times with different logical values 1 and 0. Please help to point out how to count the number of times each elements of this A matrix having 1 value. Any suggestion would be much appreciated!
A1 = 1 0 0 1 0 1 0
0 1 0 1 0 0 0
0 1 1 0 0 1 0
0 1 1 0 1 0 1
A2 = 1 0 0 0 0 1 0
0 1 0 0 0 0 0
0 1 1 1 0 1 0
0 1 1 1 1 0 1
A3 = 0 0 0 0 0 1 1
0 1 1 1 1 0 0
0 0 0 0 0 0 0
0 0 0 0 0 0 1
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Réponse acceptée
Stephen23
le 21 Sep 2018
Modifié(e) : Stephen23
le 21 Sep 2018
Simple: use one 3D array:
A = cat(3,...
[1 0 0 1 0 1 0
0 1 0 1 0 0 0
0 1 1 0 0 1 0
0 1 1 0 1 0 1],...
[1 0 0 0 0 1 0
0 1 0 0 0 0 0
0 1 1 1 0 1 0
0 1 1 1 1 0 1],...
[0 0 0 0 0 1 1
0 1 1 1 1 0 0
0 0 0 0 0 0 0
0 0 0 0 0 0 1]);
And then:
>> sum(A,3)
ans =
2 0 0 1 0 3 1
0 3 1 2 1 0 0
0 2 2 1 0 2 0
0 2 2 1 2 0 3
Note: if your arrays are in one cell array C then you can easily conver this into a 3D array:
A = cat(3,C{:});
If you have lots of separate variables, then you need to fix your code design.
Plus de réponses (1)
Fangjun Jiang
le 21 Sep 2018
Constructing your data as 3d matrix will make it easy.
A(1,:,:) =[ 1 0 0 1 0 1 0
0 1 0 1 0 0 0
0 1 1 0 0 1 0
0 1 1 0 1 0 1];
A(2,:,:) = [1 0 0 0 0 1 0
0 1 0 0 0 0 0
0 1 1 1 0 1 0
0 1 1 1 1 0 1];
A(3,:,:) = [0 0 0 0 0 1 1
0 1 1 1 1 0 0
0 0 0 0 0 0 0
0 0 0 0 0 0 1];
m=4;
n=5;
sum(A(:,m,n))
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