Calculate true in binary array specifically

Hello!

I have a boolean one-dimensional array, like

binary = [0,0,0,1,0,1,0,1,1,1,0,1,1,1,0,0,0,1,1,0 ..., 0]

And I like to squeeze from this the following:

[1, 1, 3, 3, 2, ...]

So, I would like to calculate how many 1s (Trues) encounter in row. It is possible to write a loop somehow, like:

 for i=1:size(array)

            if B(14:i)== 1
               count = count + 1;
            else:
               count = 0;
       Result_Array.append(count) % I do not know builtin function exaclty.
  end

Is it correct..? And I would like to know, if there is a standart matlab function for this purpose.

Thank you very much!

Answer 1

[Stephen23]

This is MATLAB, so you don't need to use loops to solve every little task:

>> V = [0,0,0,1,0,1,0,1,1,1,0,1,1,1,0,0,0,1,1,0,0];
>> D = diff([0,V,0]);
>> find(D<0)-find(D>0)
ans =
 1   1   3   3   2

[Ivan Volodin]

Thank you! I just do not feel this language.. Not yet