c file name from grt generated code

6 vues (au cours des 30 derniers jours)
Chirag Jagadish
Chirag Jagadish le 26 Sep 2018
Commenté : Chirag Jagadish le 11 Jan 2019
I have a tlc file which accesses the c file name generated through grt.tlc
%assign modelFileName = LibGetSourceFileSection(fileIdx, "Name")
Some times without any reason, the above code returns the complete path of the file and at most times only the name of the c or header file.
How can i filter out the complete path details and get only the file name from the string that is returned above?
Example Most of the time, modelFileName is populated as file name.c or file name.h Some times, it comes back as D:\MyGenFiles\StorageLoc\_sharedutils\<c file name>.c
How do i remove the "D:\MyGenFiles\StorageLoc\_sharedutils\" part from the string above in tlc.
I have to do this only in the tlc environment.
  1 commentaire
Chirag Jagadish
Chirag Jagadish le 26 Sep 2018
this relates to handling strings in tlc

Connectez-vous pour commenter.

Réponse acceptée

Mark McBroom
Mark McBroom le 11 Jan 2019
Probably the easiest approach is to write a simple MATLAB function that takes as an argument the modelFileName, then uses fileparts() to strip off the directory name and returns the file name. Then call this MATLAB function from TLC using the built-in TLC function FEVAL().
  1 commentaire
Chirag Jagadish
Chirag Jagadish le 11 Jan 2019
Exactly what i did. I made a new m file for this and made the FEVAL call it. FEVAL call from tlc makes only the first parameter available in the tlc. So i made a suitable m file and called it.
Thanks for the answer though

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Simulink Coder dans Help Center et File Exchange

Produits


Version

R2015b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by