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Problem in Plotting bar graph with two y axis (Bars overlapping)

9 vues (au cours des 30 derniers jours)
Ahmad Bilal
Ahmad Bilal le 26 Sep 2018
Commenté : Adam Danz le 19 Mai 2020
Hi, I have the following code:
clc;
close all;
clear all;
sheet ='Src_1MIC_Array1';
dataset = xlsread('AllSource_MicArr1.xlsx',sheet,'A4:T51');
ratio_tau_diff = dataset(:,15);
abs_tau_diff = dataset(:,18);
yyaxis left
bar(ratio_tau_diff,'r')
ylabel('Values of ratio tau diff');
yyaxis right
bar(abs_tau_diff,'b')
xlabel('Mic Array 1 pair combinations')
ylabel('Values of abs tau diff');
title('Relative and Absolute differences for Time delays (Tau) (1st Mic Array)');
end
The problem is i am getting overlapping bar graphs. how can I make suitable changes in a code so that they do not come overlap but separately. Thanks
  4 commentaires
Ahmad Bilal
Ahmad Bilal le 26 Sep 2018
I have tried this one but it is showing again not the required result.
yyaxis left
bar(ratio_tau_diff,'r')
ylabel('Values of ratio tau diff');
yyaxis right
bar(abs_tau_diff,'b')
ylim([-0.9 2]);
xlabel('Mic Array 1 pair combinations')
ylabel('Values of abs tau diff');
title('Relative and Absolute differences for Time delays (Tau) (1st Mic Array)');
Can you hep me in this regard??
Ahmad Bilal
Ahmad Bilal le 26 Sep 2018
Can you please modify the code for me. thanks

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Réponses (1)

jonas
jonas le 27 Sep 2018
The key here is to plot the two sets of bars as grouped. However, since they are on different axes you cannot plot the two data sets at the same time and thus cannot utilize the standard grouping option. Instead, you create fake groups by padding each vector with NaN's.
% Some data to play with
y1=rand(1,5).*10; %row vector with first set of data
y2=rand(1,5); %row vector with second set of data
% Create two axes
ax1=axes;
ax2=axes('xcolor','none','yaxislocation','right','color','none');
linkaxes([ax1 ax2],'x')
% Pad data with nans
y1=[y1;nan(1,numel(y1))];
y2=[nan(1,numel(y2));y2];
% plot data
axes(ax1);hold on
bar(y1')
axes(ax2);hold on
bar(y2','facecolor',[1 0 0])
xlim([0 length(y2)+1])
  2 commentaires
Lars Abrahamsson
Lars Abrahamsson le 19 Mai 2020
box on
doesn't work anylonger though
Adam Danz
Adam Danz le 19 Mai 2020
What does that mean? box on certainly still works (r2020a). 'box' isn't mentioned anywhere on this thread.

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