MATLAB solving BVP using bvp4c
8 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I am trying to solve a BVP in matlab using the bvp4c function. The following equation is a 3rd order linear homogeneous ODE with constant coefficients. I have solved second order linear and non-linear but I can't seem to figure out how to do a third order. I cannot find and documentation on how to make this adjustment.
The equation: y''' = a*h'
with boundary conditions y(0) = 0.3; y(15) = 0.7; y'(0) = 0;
The main code I have tried is below:
init = bvpinit(linspace(1,15,10),[0,0]);
sol = bvp4c(@rhs_bvp, @bc_bvp, init);
x = linspace(1,15,100);
BS = deval(sol, x);
plot(x,BS(1,:));
using the bc_bvp funtion below:
function [ bc ] = bc_bvp( yl, yr )
hi = 0.3;
ho = 0.7;
bc = [yl(1) - hi;
yl(2);
yr(1) - ho];
end
and the rhs_bvp function below:
function [ rhs ] = rhs_bvp( x, y )
a = 26;
rhs = [y(3); a*y(2)];
end
and I get this error:
Index exceeds matrix dimensions.
Error in rhs_bvp (line 8)
rhs = [y(3); a*y(2)];
Error in bvparguments (line 105)
testODE = ode(x1,y1,odeExtras{:});
Error in bvp4c (line 130)
bvparguments(solver_name,ode,bc,solinit,options,varargin);
Any help would be greatly appreciated.
Réponse acceptée
Torsten
le 5 Oct 2018
If h' = y', try
function main
init = bvpinit(linspace(1,15,10),[0,0,0]);
sol = bvp4c(@rhs_bvp, @bc_bvp, init);
x = linspace(1,15,100);
BS = deval(sol, x);
plot(x,BS(1,:));
end
function [ rhs ] = rhs_bvp( x, y )
a = 26;
rhs = [y(2); y(3); a*y(2)];
end
function [ bc ] = bc_bvp( yl, yr )
hi = 0.3;
ho = 0.7;
bc = [yl(1) - hi;
yl(2);
yr(1) - ho];
end
Best wishes
Torsten.
2 commentaires
Torsten
le 5 Oct 2018
https://en.wikipedia.org/wiki/Ordinary_differential_equation
Section "Reduction of order"
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Boundary Value Problems dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!