How to generate numbers from probability mass function?

35 vues (au cours des 30 derniers jours)
Clarisha Nijman
Clarisha Nijman le 9 Oct 2018
Hallo,
Given a probability mass function defined as P(X=3)=0.2, P(X=7)=0.3 and P(X=10)=0.5, I want to generate randomly 30 numbers (values for X) with this probability mass function as base. But I really have no idea how and where to start.
Can somebody help me?
Thank you in advance

Réponse acceptée

Torsten
Torsten le 9 Oct 2018
Modifié(e) : Torsten le 9 Oct 2018
n = 30;
X = zeros(n,1);
x = rand(n,1);
X(x <= 0.5) = 10;
X(x > 0.5 & x <= 0.8) = 7;
X(x > 0.8) = 3;
  3 commentaires
Torsten
Torsten le 10 Oct 2018
For an explanation, see
https://stats.stackexchange.com/questions/26858/how-to-generate-numbers-based-on-an-arbitrary-discrete-distribution
Clarisha Nijman
Clarisha Nijman le 19 Oct 2018
tnx u!

Connectez-vous pour commenter.

Plus de réponses (3)

Bruno Luong
Bruno Luong le 9 Oct 2018
A more generic method:
p = [0.2 0.3 0.5];
v = [3 7 10];
n = 10000;
c = cumsum([0,p(:).']);
c = c/c(end); % make sur the cumulative is 1
[~,i] = histc(rand(1,n),c);
r = v(i); % map to v values
  1 commentaire
Clarisha Nijman
Clarisha Nijman le 19 Oct 2018
This answer works for me the best. I need this to do random column sampling (sampling some columns of a very big matrix A)

Connectez-vous pour commenter.


Jeff Miller
Jeff Miller le 20 Oct 2018

With Cupid you could write:

v = [3 7 10];       % the values
p = [0.2 0.3 0.5];  % their probabilities
rv = List(v,p);     % a random variable with those values & probabilities
n = 10000;
randoms = rv.Random(n,1);  % generate n random values of the random variable
  3 commentaires
Jeff Miller
Jeff Miller le 20 Oct 2018
Did you download the Cupid files (see the link in my answer)? These define the List class (which handles the cumulative distribution behind the scene). Do the other Cupid demos run correctly?
Well, Cupid may be overkill for your problem, but it does have a lot of flexibility.
Clarisha Nijman
Clarisha Nijman le 20 Oct 2018
Ok, tnx Jeff, I'll check it!

Connectez-vous pour commenter.


PARTHEEBAN R
PARTHEEBAN R le 22 Mai 2021
A random variable X has cdf F(x) = { 0 , if x < − 1 a(1 + x ) , if − 1 < < 1 1 , if x ≥ 1 . Find (1) the value of a, (2) P(X > 1/4 ) and P ( − 0 . 5 ≤ X ≤ 0 ) .

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by