Assume
a1=[1 5 8];
b1=[6 4 5];
a2=[1 2 3 4 5 6 7 8];
Now I want to create a matching vector with values repeated as follows:
b2=[6 6 6 6 4 4 4 5];
Thanks in advance!

2 commentaires

Kevin Chng
Kevin Chng le 16 Oct 2018
Have you tried it?
KSSV
KSSV le 16 Oct 2018
Modifié(e) : KSSV le 16 Oct 2018
Whats the logic behind b2? If it is a mere repeating...read about repelem and repmat.

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 Réponse acceptée

Andrei Bobrov
Andrei Bobrov le 16 Oct 2018

0 votes

b2 = b1(cumsum(ismember(a2,a1)));

1 commentaire

Florian
Florian le 16 Oct 2018
Many thanks Andrei, also for answering my other question!

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Plus de réponses (1)

Bruno Luong
Bruno Luong le 16 Oct 2018
Modifié(e) : Bruno Luong le 16 Oct 2018

1 vote

Another method:
[~,loc] = histc(a2,a1);
b2 = b1(loc)
yet another one
b2 = b1(interp1(a1,1:length(a1),a2,'previous'))

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