I wrote this script
clc
clear
for ro=0.01:0.01:0.5
clear('alpha')
for alpha=0.25:0.25:4
clear('beta')
for beta=0.25:0.25:4
disp([ro', alpha',beta'])
end
when I run it and the result shows up it doesn't start with initial values which is (0.25,0.25) and take diffrent one each time i run the script thanks

 Réponse acceptée

madhan ravi
madhan ravi le 24 Oct 2018

0 votes

ro=0.01:0.01:0.5
alpha=0.25:0.25:4
beta=0.25:0.25:4
for i = 1:numel(ro)
for l = 1:numel(alpha)
for k = 1:numel(beta)
disp([ro(i)', alpha(l)',beta(k)'])
end
end
end

5 commentaires

Ammar kreem
Ammar kreem le 24 Oct 2018
dear Madhan i tried your answer but the values dosnt start with 0.01 0.25 0.25 which i need to
madhan ravi
madhan ravi le 24 Oct 2018
give an example of your output just few rows so the pattern what you require is understood
Ammar kreem
Ammar kreem le 24 Oct 2018
dear Madhan this what I got 1.9100 1.0000 3.5000
1.9100 1.0000 3.7500
1.9100 1.0000 4.0000
and this what i need
0.01 0.25 0.25
0.01 0.25 0.5
and end with 2 4 4
thanks for everything
madhan ravi
madhan ravi le 25 Oct 2018
You want to display the numbers like the below? 0.01 0.25 0.25
0.01 0.25 0.5
2 4 4
madhan ravi
madhan ravi le 25 Oct 2018
disp([ro(i), alpha(l),beta(k)])

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Plus de réponses (1)

Ammar kreem
Ammar kreem le 25 Oct 2018

0 votes

this how i want the result

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