How to plot Fourier series with 100 terms ?

I'm trying to plot the attached Fourier series for 100 terms but the plot shows values reaching 40 when I'm expecting maximum values to be around 4. This is what I've managed so far. I would appreciate if someone could help me understand where I'm going wrong

t=-pi:pi/10:pi;
vt=zeros(1,length(t));

for m=1:1:2;
    bm=(8/m*pi)*(1-cos(m*pi/2))
    vt= vt + bm*sin(m*t);
end

plot(t,vt)

[Korosh Agha Mohammad Ghasemi]

clear all;clc; 
syms x  
pi=3.14; 
sum=0;  
y=exp(x);   %function you want 
a0=(1/pi)*int(y,x,-pi,pi); 
for n=1:3 
        %finding the coefficients 
    an=(1/pi)*int(y*cos(n*x),x,-pi,pi); 
    bn=(1/pi)*int(y*sin(n*x),x,-pi,pi);    
    sum=sum+(an*cos(n*x)+bn*sin(n*x));  
end 
% https://www.instagram.com/koroshkorosh1/
ezplot(x,y,[-pi,pi]); 
grid on;hold on;  
ezplot(x,(sum+a0/2),[-pi,pi]); 
% https://www.instagram.com/koroshkorosh1/

Answer 1

[Bruno Luong]

for m=1:1:2;

And you think this makes 100 terms??

Then

bm=(8/m*pi)*(1-cos(m*pi/2))

So you multiply by pi? Look like you need to concentrate on the parenthesis:

bm=8/(m*pi)*(1-cos(m*pi/2));

[Korosh Agha Mohammad Ghasemi]

clear all;clc; 
syms x  
pi=3.14; 
sum=0;  
y=exp(x);   %function you want 
a0=(1/pi)*int(y,x,-pi,pi); 
for n=1:3 
        %finding the coefficients 
    an=(1/pi)*int(y*cos(n*x),x,-pi,pi); 
    bn=(1/pi)*int(y*sin(n*x),x,-pi,pi);    
    sum=sum+(an*cos(n*x)+bn*sin(n*x));  
end 
% https://www.instagram.com/koroshkorosh1/
ezplot(x,y,[-pi,pi]); 
grid on;hold on;  
ezplot(x,(sum+a0/2),[-pi,pi]); 
% https://www.instagram.com/koroshkorosh1/