Effacer les filtres
Effacer les filtres

Collision Problem (Square 2d)

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Jake Simmonds
Jake Simmonds le 2 Nov 2018
Commenté : aliyah islam le 18 Déc 2019
Hello there, i am trying to write some code that plots a square moving along a line with a certain velocity when the centre of the squares coordinates get within a certain tolerance the direction of the velocity becomes negative and so it 'bounces' off the wall. My code is below but the constraints in terms of direction don't seem to be working any insight would be greatly appreciated. Best Regards
fps = 20;
dt = 1/fps;
tmax = 10;
t = 0;
theta = 0;
dtheta = 1/20;
p = transpose([20,20,1]);
v = transpose([50,25,1]);
Vobj = transpose([2, -2, 1; 2,2,1; -2, 2, 1; -2, -2, 1]);
while t < tmax
x = p + t*v;
if x(1)<= 5 || x(1) >= 95
v(1)=-v(1);
elseif x(2)<= 5 || x(2) >= 95
v(2)=-v(2);
end
p = x;
% Transformations
T = [1,0,p(1);0,1,p(2);0,0,1];
S = [1+0.2*sin(2*t),0,0; 0,1+0.2*sin(2*t),0;0,0,1];
R = [cos(theta),sin(theta),0 ;-sin(theta),cos(theta),0;0,0,1];
% Application of Transformations
V = R*S*T*Vobj;
fill(V(1,:),V(2,:),'r')
hold on
axis([0,100,0,100])
hold off
shg;
pause(0.3);
% Updates
t = t + dt;
theta = theta + dtheta;
end
  1 commentaire
aliyah islam
aliyah islam le 18 Déc 2019
Did you end up figuring this problem out? If so have you still got the matlab code for it, as i have a similar problem to solve. Thanks

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Réponses (1)

madhan ravi
madhan ravi le 2 Nov 2018
fps = 20;
dt = 1/fps;
tmax = 10;
t = 0;
x =[20,20,1];
v = [50,25,1];
ctr=1;
while t < tmax
p(ctr,:) = x + t*v;
if p(1) < 5 || p(1) > 95 || p(2) < 5 || p(2) > 95
p(ctr,:) = x + t*(-v);
else
p(ctr,:) = x + t*v;
end
plot(p(1),p(2),'o')
hold on
axis([0,100,0,100])
hold off
pause(1);
t = t + dt;
end
  3 commentaires
Jake Simmonds
Jake Simmonds le 2 Nov 2018
This still has the same issue as my above code once it enters the tolerance it just disappears
Jake Simmonds
Jake Simmonds le 2 Nov 2018
It's a matter of changing the direction the plot goes after it is in the critical zone so to speak.

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