How can I plot 3D surface x^3 + y^3 + z^3 = 1, where x, y, z are in unit closed interval in MATLAB ?.

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I want to plot a surface x^3 + y^3 + z^3 = 1, where x, y, z are in unit closed interval. The MATLAB is not displaying the plot. Perhaps there occur some complex roots. Please help me to write its code. Thanks in advance.

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madhan ravi
madhan ravi le 11 Nov 2018
Modifié(e) : madhan ravi le 11 Nov 2018
syms x y z
fimplicit3(x^3+y^3+z^3==1,[-1 1 -1 1 -1 1])
  11 commentaires
Bruno Luong
Bruno Luong le 11 Nov 2018
Modifié(e) : madhan ravi le 11 Nov 2018
Thanks
madhan ravi's reply: Anytime :) @Bruno

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Bruno Luong
Bruno Luong le 11 Nov 2018
[x,y,z]=ndgrid(linspace(-1,1,33));
v=x.^3+y.^3+z.^3-1;
close all
p = patch(isosurface(x,y,z,v,0));
p.FaceColor = 'red';
daspect([1 1 1])
view(120,-30);
axis tight
camlight
lighting gouraud
  15 commentaires
Torsten
Torsten le 26 Juil 2022
Maybe you mean
x = linspace(0, 1,100 ).';
f = @(x) (x<0.5) .* (30.*x) + (x>=0.5).* (70.*x-20 );
g = @(x) (x<0.5).* (30.*(1-x)) + (x>=0.5).* (50-70.*x ) ;
figure
plot(x, [f(x), g(x)], 'linewidth', 1.5 )
Amna Habib
Amna Habib le 26 Juil 2022
Yes, exactly. The same is required.
Thanks a lot @Torsten.

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