Index exceeds the number of array elements (1).

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Guilherme Lopes de Campos
Guilherme Lopes de Campos le 11 Nov 2018
Commenté : madhan ravi le 11 Nov 2018
Hi community Matlab, My programme is generating the following error,
if true
function dxdt = semibrx(t,x,k,Kc,V0,v0,Cb0)
% x(1)= Ca, x(2) = Cb, x(3) = Cc, x(4) = Cd;
rA = -k*(x(1)*x(2)-(1/Kc)*x(3)*x(4));
V = V0+v0*t;
dxdt = [
rA-(v0/V)*x(1);
rA + (v0/V)*(Cb0-x(2));
-rA-(v0/V)*x(3);
-rA-(v0/V)*x(4)
]
end
if true
clear all;
k = 9e-5; v0= 0.05 ; V0 = 200; Cb0 = 10.93; Ca0= 7.72;
Kc = 1.08;
x0 = [Ca0 0 0 0 ]; tspan = [0 1e2];
[t x] = ode45(@equilibrio,tspan,Kc,x0,[],k,v0,V0,Cb0);
Ca = x(:,1);
Cb = x(:,2);
Cc = x(:,3);
Cd = x(:,4) ;
V = V0 + v0*t; Xa = (Ca0*V0-Ca.*V)/(Ca0*V0); rA = -k*(x(1)*x(2)-(1/Kc)*(x(3)*x(4)));
%subplot(1,2),
plot(t,Ca,t,Cb,':',t,Cc,'.-',t,Cd,'--');
xlabel('t(s)'),ylabel('Concentration(mol/dm^3)'), legend ('C_A','C_B','C_C','C_D')
%subplot(1,2),
%plot(t,rA), xlabel('t(s)'),ylabel ('Reaction rate (mol/dm^3s)')
%plot(t,Xa),xlabel('t(s)'),ylabel('Conversão')
end
end
The program shows error: Index exceeds the number of array elements(1).
Would you help me please?
Thanks,
Guilherme Lopes de Campos
  5 commentaires
madhan ravi
madhan ravi le 11 Nov 2018
See my answer below
Guilherme Lopes de Campos
Guilherme Lopes de Campos le 11 Nov 2018
Thank you very much Community, for help!

Connectez-vous pour commenter.

Réponse acceptée

madhan ravi
madhan ravi le 11 Nov 2018
Modifié(e) : madhan ravi le 11 Nov 2018
clear all;
Ca0= 7.72;
x0 = [Ca0 0 0 0 ]; tspan = [0 1e2];
[t x] = ode45(@equilibrio,tspan,x0); %FUNCTION CALLING
Ca = x(:,1);
Cb = x(:,2);
Cc = x(:,3);
Cd = x(:,4) ;
figure
plot(t,Ca)
xlabel('t(s)')
ylabel('Concentration(mol/dm^3)')
legend ('C_A')
figure
plot(t,Cb,':')
xlabel('t(s)')
ylabel('Concentration(mol/dm^3)')
legend('C_B')
figure
plot(t,Cc,'.-')
xlabel('t(s)')
ylabel('Concentration(mol/dm^3)')
legend ('C_C')
figure
plot(t,Cd,'--')
xlabel('t(s)')
ylabel('Concentration(mol/dm^3)')
legend ('C_D')
function dxdt = equilibrio(t,x)
k = 9e-5; v0= 0.05 ; V0 = 200; Cb0 = 10.93;
Kc = 1.08;rA = -k*(x(1)*x(2)-(1/Kc)*x(3)*x(4));
V = V0+v0*t;
dxdt = [rA-(v0/V)*x(1);
rA + (v0/V)*(Cb0-x(2));
-rA-(v0/V)*x(3);
-rA-(v0/V)*x(4)]
end
  2 commentaires
Guilherme Lopes de Campos
Guilherme Lopes de Campos le 11 Nov 2018
Thank you very much Madhan!
madhan ravi
madhan ravi le 11 Nov 2018
Anytime :)

Connectez-vous pour commenter.

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