Effacer les filtres
Effacer les filtres

How to speed up a euclidean distance calculation between one pixel and many others

2 vues (au cours des 30 derniers jours)
Stephanie Diaz
Stephanie Diaz le 14 Nov 2018
Commenté : Guillaume le 14 Nov 2018
I am calculating the euclidean distance between a pixel (x,y) and many other pixels in a matrix. I identify the x and y coordinates of the pixels beforehand, and save their x and y values in two column vectors x2 and y2, respectively I currently use the following:
distance = (sqrt((x2-x).^2 + (y2-y).^2))
This works, but is very slow. How can I speed this up?
  1 commentaire
Guillaume
Guillaume le 14 Nov 2018
This works, but is very slow.
How did you establish that it is slow?
>> coord = rand(1e6, 2);
>> tic; distance = sqrt((coord(:, 1) - coord(1, 1)).^2 + (coord(:, 2) - coord(1, 2)).^2); toc
Elapsed time is 0.029055 seconds.
As you can see it takes around 30 milliseconds on my computer to process a million coordinates.
Most likely, it's another part of your program that is slow, so show us your code.
Note that using hypot would be safer (albeit neglibly slower) than doing the calculation yourself:
distance = hypot(x2-x, y2-y);

Connectez-vous pour commenter.

Réponses (1)

madhan ravi
madhan ravi le 14 Nov 2018
use norm()
  1 commentaire
Stephanie Diaz
Stephanie Diaz le 14 Nov 2018
OK, but how do i apply this to more than one pixel? Since "norm(b-a)." only gives me one value

Connectez-vous pour commenter.

Catégories

En savoir plus sur Resizing and Reshaping Matrices dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by