trying to create a loop that finds a value in an array and creates a matrix with it

1 vue (au cours des 30 derniers jours)
I have an array TT where the first column is matlab serial date numbers and each other column is data for various variables.
I want to create a loop where the interation is
i = datenum(2018,1,1,00,00,00):0.208:datenum(2018,12,4,00,00,00)
0.208 is the difference between half hour periods in matlab serial date numbers. so i should loop through all the values in my first column. The problem is that these values are floating points. additionally, i'm not sure how to create a matrix with this. For more detail, what I want to do is create a matrix where for each i value, the matrix either has the corresponding variable data or if there is no value in TT that matches i, it'll insert an NaN into the matrix. I hope this makes sense. Any guidance would be appreciated.
  3 commentaires
Stephen23
Stephen23 le 17 Nov 2018
Modifié(e) : Stephen23 le 17 Nov 2018
"0.208 is the difference between half hour periods in matlab serial date numbers"
Almost. Serial date numbers count up in days, so one half hour has a value of
>> 1/24/2
ans = 0.020833
Susan Santiago
Susan Santiago le 19 Nov 2018
You said in a .mat file so I assume you mean my array. This is it. If this is not what you meant, please let me know. And yes thank, I miswrote. It should be 0.020833

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Walter Roberson
Walter Roberson le 17 Nov 2018
If you have a new enough version then I recommend changing to timetable objects and using retime()
Otherwise consider using interp1() . If that is not suitable, then use ismembertol() to find matching items. If your system is too old to have ismembertol() then loop with testing ranges of values.
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Susan Santiago
Susan Santiago le 19 Nov 2018
I have the 2017 version. I'll look into ismembertol. Thanks

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