how to order a matrix?
    4 vues (au cours des 30 derniers jours)
  
       Afficher commentaires plus anciens
    
    Sky Scrapper
 le 30 Nov 2018
  
    
    
    
    
    Commenté : Sky Scrapper
 le 3 Déc 2018
            hi, 
Say, I have a matrix, 
     A                       B              C                D    
-6760,691	       0	      -1   	         0                   
-3380,495	      1	      -1	         1
-6760,691	       0	      -1	         0
-3380,395	      -1	       0	        -1
-3380,395	      -1              0	        -1
-6760,691	 	0	      -1	         0
-3380,495	 	-1	      -1	         1
-6760,691	  	 0	      -1        	 0
-3380,395	  	-1      	0	        -1
3380,195	                 1      	0	         1
And I want to get,
          A                       B                    C                D
-6760,691                   0                   -1                 0
-3380,495                   1                   -1                 1
                                   -1                   -1                1        
-3380.395                  -1                    0                -1
3380,195	                   1	                 0                 1            
Here, I need to order the unique values of A which is done on the 1st column. I'll have to write the different patterns of B, C, D on the basis of same value of A. And, if there is any more repeated values of B,C,D for the same value of A, i'll have to keep only 1 pattern (row).   
Can anyone please help me?                              
0 commentaires
Réponse acceptée
  Andrei Bobrov
      
      
 le 30 Nov 2018
        
      Modifié(e) : Andrei Bobrov
      
      
 le 1 Déc 2018
  
      EDIT
>> B = [-3380.5            1           -1            1
      -6760.7            0           -1            0
      -3380.4           -1            0           -1
      -3380.4           -1            0           -1
      -6760.7            0           -1            0
      -3380.5           -1           -1            1
      -6760.7            0           -1            0
      -3380.4           -1            0           -1
       3380.2            1            0            1];
>> A = unique(B,'rows')
A =
      -6760.7            0           -1            0
      -3380.5           -1           -1            1
      -3380.5            1           -1            1
      -3380.4           -1            0           -1
       3380.2            1            0            1
>> A([false;diff(A(:,1)) == 0],1) = nan
A =
      -6760.7            0           -1            0
      -3380.5           -1           -1            1
          NaN            1           -1            1
      -3380.4           -1            0           -1
       3380.2            1            0            1
>>  
4 commentaires
  Andrei Bobrov
      
      
 le 3 Déc 2018
				A = [      -3380.5            1           -1            1       0     0    0      0
-6760.7            0           -1            0        0     1    0      0
-3380.4           -1            0           -1        0     1    1      0
-3380.4           -1            0           -1        1      0    0     0
-6760.7            0           -1            0         0     0    1     0
-3380.5           -1           -1            1         1     0    1     0
-6760.7            0           -1            0          1    0     1    1
-3380.4           -1            0           -1          0    0    0     1
3380.2            1            0            1           0    1    0     1];
[~,b] = unique(A(:,1:4),'rows');
B = A(b,:);
B([false;diff(B(:,1))==0],1) = nan;
Plus de réponses (0)
Voir également
Catégories
				En savoir plus sur Logical dans Help Center et File Exchange
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!

