How do you centre your plot at '0' on the X-axis after performing a Fourier transform?

33 vues (au cours des 30 derniers jours)
Matt
Matt le 16 Juil 2012
I have a generated signal which I perform an fft on as well as zero-padding it with 5000 zeros. The problem I have is that the resulting plot is centered at 2500 (i.e. half of 5000).
Is it possible for me to shift my plot 2500 spaces to left on my X-axis so that the plot is centered on 0?

Réponses (1)

Dr. Seis
Dr. Seis le 16 Juil 2012
Modifié(e) : Dr. Seis le 16 Juil 2012
fftshift might be what you are looking for. Does this example help?
dt = 0.1; % Fs = 1/dt;
N = 16;
t = (0:N-1)*dt;
g = randn(size(t));
Nyq = 1/2/dt;
df = 1/N/dt;
f = -Nyq : df : Nyq-df;
G = fftshift(fft(g));
figure; plot(f,G);
[EDIT]
f1 = -3; % minimum frequency
f2 = 3; % maximum frequency
idx = f1 < f & f < f2;
figure; plot(f(idx), G(idx));
  2 commentaires
Matt
Matt le 16 Juil 2012
I have used abs(fftshift(fft(x))) but that just gives me my plot at the middle of all my values including the zero's. In your example you do not zero pad. I need to use many zero's in my case...
Lamda1 = .003;
N = pi./Lamda1;
Step1 = .03;
A4 = [-N/2:Step1:(N/2)-Step1];
R4 = zeros(size(A4));
R4 = (0.5 + (0.5)*((1 - (A4.^2)).^2));
R4 = 10*log10(R4);
A4 = asin(A4);
figure (10); plot(A4,R4)
FD4 = fft(R4, 200000) / N;
%figure (11); plot(abs(FD4));
figure (12); plot(abs(fftshift(FD4)))
Dr. Seis
Dr. Seis le 16 Juil 2012
Modifié(e) : Dr. Seis le 16 Juil 2012
Why not specify a range using logicals... continuing my example above:
f1 = -3; % minimum frequency
f2 = 3; % maximum frequency
idx = f1 < f & f < f2;
figure; plot(f(idx), G(idx));
Note: Your "N" will be based on the number you pad up to (i.e., 200000) for determining what "f" is for your data.

Connectez-vous pour commenter.

Catégories

En savoir plus sur Graphics Object Identification dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by