im2col error in size
5 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hi this is my code:
R=rand(162,72);
r=im2col(R,[2 2],'sliding');
R1=col2im(r,[2 2],size®,'sliding');
the size of R is [162 72];
when I use line 1 it is OK. It gives me a a matrix r with size of r=[4 11431]
but at line 2 to obtain R, when I want to convert them to the original matrix via col2im, it give me this error:
"To RESHAPE the number of elements must not change."
Can anybody help me please and tell me what is the problem?
0 commentaires
Réponse acceptée
Image Analyst
le 16 Juil 2012
What are you really trying to do? im2col() and col2im() are confusing functions that are probably going to be deprecated soon. How did you ever stumble upon those? Can't you do what you want to do with reshape() or blockproc() or something?
3 commentaires
Image Analyst
le 16 Juil 2012
Modifié(e) : Image Analyst
le 16 Juil 2012
I'm glad you explained that because now I can recommend nlfilter() as the proper way to do what you want to do. My advice is to not use reshape() but to use nlfilter(), or alternatively blockproc() if you don't have the Image Processing Toolbox.
Plus de réponses (1)
Sean de Wolski
le 16 Juil 2012
Because you are using a 'sliding' block with im2col the number of elements in r is much bigger than the number in R. Compare:
numel(R)
numel(r)
What you have works with 'distinct' blocks as you would expect:
R=rand(162,72);
r=im2col(R,[2 2],'distinct');
R1=col2im(r,[2 2],size(R),'distinct');
5 commentaires
Image Analyst
le 17 Juil 2012
That won't happen if you don't do that im2col/col2im stuff and use nlfilter instead.
Voir également
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!