How to count NaN elements in n dimentional matrix, using counter in loop?
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How to count NaN elements in n dimentional matrix, using counter in loop?
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madhan ravi
le 1 Jan 2019
Modifié(e) : madhan ravi
le 1 Jan 2019
Without loop:
A=rand(2,2,2); % a short example with 3D matrix
A(2,2,1)=NaN; % just insert nan values to check
A(2,2,2)=NaN;
NaNs_present=nnz(isnan(A))
With loop(not necessary though):
A=rand(2,2,2);
A(2,2,1)=NaN;
A(2,2,2)=NaN;
Result=cell(1,size(A,1));
ctr=1;
for i = 1:size(A,1)
for j = 1:size(A,2)
for k = 1:size(A,3)
Result{ctr}=isnan(A(i,j,k))
ctr=ctr+1;
end
end
end
NaNs_present=nnz([Result{:}])
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Stephen23
le 1 Jan 2019
Where A is your array:
cnt = 0;
for k = 1:numel(A)
cnt = cnt+isnan(A(k));
end
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