why eq says they are not equal

I have two equal vectors a = b. When I check for equality:
y = eq(a, b)
find(y==0)
I get most of values, meaning they are NOT equal.
What would be the reason for this?
N.

5 commentaires

Jan
Jan le 19 Juil 2012
What does the "find(a==0)" do in your code?
Nuchto
Nuchto le 21 Juil 2012
Sorry, it was wrong put, "a" should be the output of eq(a,b).
Jan
Jan le 21 Juil 2012
Then please edit the question instead of adding this important information as a comment.
Nuchto
Nuchto le 22 Juil 2012
Thanks, I did.
Jan
Jan le 22 Juil 2012
@Nuchto: Is your problem solved?

Connectez-vous pour commenter.

 Réponse acceptée

Muruganandham Subramanian
Muruganandham Subramanian le 19 Juil 2012
Modifié(e) : Walter Roberson le 22 Juil 2012

0 votes

Hi Nuchto,
Check this below link:

1 commentaire

Nuchto
Nuchto le 19 Juil 2012
I have checked the help, but it didn't answer to my question.

Connectez-vous pour commenter.

Plus de réponses (2)

Jan
Jan le 19 Juil 2012
Modifié(e) : Jan le 19 Juil 2012

0 votes

To compare two vectors use:
r = isequal(a, b)
or to find the difference between vectors (or other arrays) of the same size:
any(a - b)
Note, that the later replies FALSE even for ones(1,10) and ones(1,1).
If you only assume, that the vectors have equal values, check a - b and note, that the limited precision of the type double leads to effects like:
03. - 0.2 ~= 0.1
Then check "almost equal" by:
limit = eps(max(max(abs(a(:)), abs(b(:)))));
% or: eps(max(abs(a(:)), abs(b(:))));
% or: the same times 10
a_eq_b = isequal(size(a), size(b)) & all(abs(a - b) < limit);
The choise of the limit depends on the physical meaning of the variables. There is no unique definition to distinguish measurement noise from noise caused by numerical artifacts for a tiny values.

Catégories

En savoir plus sur MATLAB dans Centre d'aide et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by