Replacing elements in Array
6 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I have two 48 x 61 matrices, LE and Q. If the first and last row value of LE are the same, for those rows, I want the values of Q to equal Q(:, 61).
This is what I initially wrote, but am getting an error message.
C = find(LE(:,1) == LE(:,61)); % Outputs rows in which first and last values are equivalent.
Q(C,:) = Q(C, 61); % For all values in rows C, make every value in that row (of Q) the last value in row Q.
Error: subscript assignment dimension mismatch.
Any suggestions? Thanks!
1 commentaire
Image Analyst
le 20 Juil 2012
It's always nice if the poster supplies some sample data in advance to make it easy for people to try things for her. I mean, why make it hard for people to help you?
Réponse acceptée
Plus de réponses (1)
Albert Yam
le 20 Juil 2012
When length(C) > 1 , Matlab doesn't know how to replace the values.
(length(C) x 61) matrix , and a length(C) vector
If you loop it for every C, it should work, someone else might be able to point out a way without looping.
C = find(LE(:,1) == LE(:,61));
for ii=1:length(C)
Q(C(ii),:) = Q(C(ii), 61);
end
0 commentaires
Voir également
Catégories
En savoir plus sur Matrices and Arrays dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!