calculate a function based on array data

I need to calculate dispersion effect based on how much farther the observer from the chimney.
I came up with this kind calculation :
% edited for full variable
hasil = str2num(get(handles.hasil, 'string'));
koefisiena = str2num(get(handles.koefisiena, 'string'));
sigmaz = str2num(get(handles.sigmaz, 'string'));
vangin = str2num(get(handles.vangin, 'string'));
for distance= [0.25; 0.5; 0.75; 1; 1.25; 1.5; 1.75; 2; 2.25; 2.5;];
y= {(hasil./(2*3.14*(koefisiena*(distance.^0.894))*sigmaz*vangin))};
end
however it gives an error output
Error using ./
Matrix dimensions must agree.
Error in desain>pushbutton2_Callback (line 520)
y= {(hasil./(2*3.14*(koefisiena*(jaraks.^0.894))*sigmaz*vangin))};
Even after changing the notation of division from matrix
./
into scalar
/
it still produces the typical error. I want to know how exactly to calculate the matrix value of a function

4 commentaires

KSSV
KSSV le 26 Fév 2019
YOu have not defined many variables.....how do you expect us to help you?
Muhammad Waqi Azizi
Muhammad Waqi Azizi le 26 Fév 2019
I've edited the code, added the variable which taken from handles as input text
Adam
Adam le 26 Fév 2019
Using the debugger is by far the easiest way to solve problems like this. Just look at the sizes of the two sides of the ./ operator on command line and it should be obvious. We have no idea what size they are since you just convert a string to get them. I assume they aren't all scalars otherwise I would not expect such an error.
Stephen23
Stephen23 le 26 Fév 2019
Modifié(e) : Stephen23 le 26 Fév 2019
"Even after changing the notation of division from matrix ./ into scalar /"
According to the MATLAB help thosee operators are actually:
See also:
Learning the difference between matrix and array operators is critical to using MATLAB.

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