Time Difference and adftest (augmented dickey fuller test)

Hello Pals,

I'm trying to run the given script but there is an error.

I'm using function[h,pvalue]=adftest.

If I'm using adftest with T, it gives me logic h=0( since time is non stationary). Therefore to ake time stationary I did detrended T to dt.

But,then my Udays goes to 0, due to which my for loop becomes false. and give me error. I have attached the excel file for the reference.

Thanks

clc; clear; close all;

[num,txt,raw]=xlsread('CHCP Loads.xlsx','Heating Load');

qHtg=num(:,end);

T =datenum(txt(2:end,1)); % given Time

dt=diff(T,1);

Udays=unique(round(dt));

for i= 1:5

ind= round(dt)==Udays(i);

peakHtg(i,1)=max(qHtg(ind));

end

[h,pval]=adftest(peakHtg);

%h=0 so we need to do the differncing

close all