I am using the lsqcurvefit function to fit a function that is dependent on two variables. Let's call these two variables, X, and Y.
If my function looks like:
can someone explain why the Jacobian to this is:
Jacobian=[X(:), Y(:), ones(size(X(:)))];
If I take df/dX, I would get "a", df/dY = "b". Why is the answer what I show it to be?
I am confused and I need to understand what is going on, since I need to change this function to something else. I wanted to start with this one, which is an example I was given, and the Jacobian is known.