Help with fmincon function

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Noemi Ambrosio
Noemi Ambrosio le 27 Mar 2019
Modifié(e) : Catalytic le 27 Mar 2019
Hello everyone!
I need help with my matlab code. I have this objective function: g = @(u) 30*u(1) + (20/2)*(u(2))^2 + (20/2)*(u(3))^2 + (10/2)*(u(4))^2 + (40/2)*(u(5))^2; and this conditions:
%initial guesses
u0 = [1 1 1 1 100000]; %
A = [];
b = [];
Aeq = [];
beq = [];
lb = 0.0 * ones(1,2,3,4);
ub = 1.0 * ones(1,2,3,4);
[x,fval,output,lambda] = fmincon(g, u0, A, b, Aeq, beq, lb, ub);
I need to find the values for different instant of times, because g is a function of time.
In this way I find only one value for each u. How can I do that and find the different values for each instant of time? I hope it is clear, thank you so much!!

Réponse acceptée

Catalytic
Catalytic le 27 Mar 2019
Modifié(e) : Catalytic le 27 Mar 2019
First of all, let's fix your code.
g = @(u) 30*u(1) + (20/2)*(u(2))^2 + (20/2)*(u(3))^2 + (10/2)*(u(4))^2 + (40/2)*(u(5))^2;
u0 = [1 1 1 1 100000]; %
lb = zeros(1,5);
ub = ones(1,5);
[u,fval,output,lambda] = fmincon(g, u0, [],[],[],[], lb, ub);
In this way I find only one value for each u. How can I do that and find the different values for each instant of time?
By writing a loop over time.
for t=1:T
g = ----- something t-dependent --------
[u(t,:),fval,output,lambda] = fmincon(g, u0, [],[],[],[], lb, ub);
end

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