To Stupid for Matrix Loop
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Hello I am Looking for a Loop, but i am not able to find the right one, this is the code i have so far:
function Copy = myfilter(IMG,x,y)
n=pixfilter(IMG,440,280)
IMG(440,280)=n;
n=pixfilter(IMG,440,281)
IMG(440,281)=n;
n=pixfilter(IMG,440,282)
IMG(440,282)=n;
n=pixfilter(IMG,440,283)
IMG(440,283)=n;
n=pixfilter(IMG,440,284)
IMG(440,284)=n;
n=pixfilter(IMG,440,285)
IMG(440,285)=n;
n=pixfilter(IMG,441,280)
IMG(441,280)=n;
n=pixfilter(IMG,441,281)
IMG(441,281)=n;
n=pixfilter(IMG,441,282)
IMG(441,282)=n;
n=pixfilter(IMG,441,283)
IMG(441,283)=n;
n=pixfilter(IMG,441,284)
IMG(441,284)=n;
n=pixfilter(IMG,441,285)
IMG(441,285)=n;
n=pixfilter(IMG,442,280)
IMG(442,280)=n;
n=pixfilter(IMG,442,281)
IMG(442,281)=n;
n=pixfilter(IMG,442,282)
IMG(442,282)=n;
n=pixfilter(IMG,442,283)
IMG(442,283)=n;
n=pixfilter(IMG,442,284)
IMG(442,284)=n;
n=pixfilter(IMG,442,285)
IMG(442,285)=n;
n=pixfilter(IMG,443,280)
IMG(443,280)=n;
n=pixfilter(IMG,443,281)
IMG(443,281)=n;
n=pixfilter(IMG,443,282)
IMG(443,282)=n;
n=pixfilter(IMG,443,283)
IMG(443,283)=n;
n=pixfilter(IMG,443,284)
IMG(443,284)=n;
n=pixfilter(IMG,443,285)
IMG(443,285)=n;
n=pixfilter(IMG,444,280)
IMG(444,280)=n;
n=pixfilter(IMG,444,281)
IMG(444,281)=n;
n=pixfilter(IMG,444,282)
IMG(444,282)=n;
n=pixfilter(IMG,444,283)
IMG(444,283)=n;
n=pixfilter(IMG,444,284)
IMG(444,284)=n;
n=pixfilter(IMG,444,285)
IMG(444,285)=n;
n=pixfilter(IMG,445,280)
IMG(445,280)=n;
n=pixfilter(IMG,445,281)
IMG(445,281)=n;
n=pixfilter(IMG,445,282)
IMG(445,282)=n;
n=pixfilter(IMG,445,283)
IMG(445,283)=n;
n=pixfilter(IMG,445,284)
IMG(445,284)=n;
n=pixfilter(IMG,445,285)
IMG(445,285)=n;
Copy=IMG
end
It is working corrctly but there must be a possible for a nice, elegant Loop. But i Never worked with This Kind of Function in Part of a Mtrix Before:
In The Skript it will be integrated like this:
C=myfilter(IMG,440:445,280:285);
Réponses (2)
James Tursa
le 11 Avr 2019
Do you mean simply this?
for i=x
for j=y
IMG(i,j) = pixfilter(IMG,i,j);
end
end
Maike-Sophie Mittelstädt
le 11 Avr 2019
0 votes
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