Calling option from menu function

The code has main menu based on ATM macine. 1-Get cash. 2-Get Balance. 3-Quit % if user choose option 1

Mainmenu= menu('Main Menu','1-Get Cash','2-Get Balance','3-Quit');

if Mainmenu ==1

In Get Cash, Another menu that the user have to choose how much to withdraw

GetCashM= menu('Withdrawal amount','20$','40$','100$','200$');

, and after that, another menu to prompt the user to select 1- checking, 2- savings,

Acct= menu('From which account','checking','Saving');

and disp how many 20 bills were dispansed that is after verifying if there are enough funds in the selected account. And when option 1 or 2 are processed, the main menu will show again. I got that done. But, If option 3- quit selected, display New checking Balance and New Saving Balance. But how can I subtract the withdraw amount from checking savings account since menu option are string I think. Even if I called it it would be 1 or 2 or 3 or 4 respectivly to withdraw amount menu.

(ex)

Sbal = 100;

if the user withdrew 20$ from Sbal . "in option 1 from whidraw amount "

"second iteration."

if MainMenu ==. 3 % if the user choose option quit after proseccing whidraw amount

NewSavBal = GetCashMenu - SBal;

but that did not do it since values inside menu were string.

Keep in mind that

• If the user closes the menu rather than making a selection, warning message should bedisplayed and the user given 2 more chances to make a selection from that menu. If they still close the menu on the 3rd attempt, an error message should be displayed that says the program has been terminated.

[Walter Roberson]

menu() does not return strings or character vectors. menu() returns the relative choice in numeric form -- first option such as the '20$' returns 1, second option such as the '40$' returns 2, and so on.

[mat geek]

Ok I got this done. But how can I do this

• If the user closes the menu rather than making a selection, warning message should be displayed and the user given 2 more chances to make a selection from that menu. If they still close the menu on the 3rd attempt, an error message should be displayed that says the program has been terminated.

should I make another while loop just for that part. Because I aleady have a while loop from after the user input till the last part where I adeed i = i+1 at the end of the while loop and the statment is while i `~= 3

this will iterate the program 3 times only.

the rest of the code.

[Walter Roberson]

warncount = 0;
while true
    MainMenu = menu(....)
    if MainMenu == 0
       if warncount == 3
           error
       else
           warning
           warncount = warncount + 1;
       end
    else
        do something appropriate
        warncount = 0;
    end
end

[mat geek]

Here is my version , and I know it's not neat, but I got everything to work except this one thing. the problem is the code does not go through Acct=1, it skips to the end of the code. I think the problem with the end function.

CBal= input('Enter your checking account balance\n');

SBal= input('Enter your Savings account balance\n');

k=0;

i = 0;

while i ~=3

Mainmenu= menu('Main Menu','1-Get Cash','2-Get Balance','3-Quit');

if Mainmenu ==1

GetCashM= menu('Withdrawal amount','20$','40$','100$','200$');

Acct= menu('From which account','Checking','Savings');

if Acct == 1 % the code does not execute this statement %% even if it's ture ???

elseif GetCashM == 1 && CBal >=20

MonOut = 1 ;

fprintf(' %d 20$ bills were dispensed\n',MonOut)

CBal = CBal - 20;

elseif GetCashM == 2 && CBal >=40

MonOut = 2;

fprintf(' %d 20$ bills were dispensed\n',MonOut)

CBal = CBal - 40;

elseif GetCashM == 3 && CBal >=100

MonOut = 5 ;

fprintf(' %d 20$ bills were dispensed\n',MonOut)

CBal = CBal - 100;

elseif GetCashM ==4 && CBal >=200

MonOut = 10 ;

fprintf(' %d 20$ bills were dispensed',MonOut)

CBal = CBal - 200;

else

fprintf('not enough funds in check account\n')

end

else

if Acct == 2

elseif GetCashM == 1 && SBal >=20

MonOut = 1 ;

fprintf(' %d 20$ bills were dispensed\n',MonOut)

NewSBal = SBal - 20;

elseif GetCashM == 2 && SBal >=40

MonOut = 2;

fprintf(' %d 20$ bills were dispensed\n',MonOut)

NewSBal = SBal - 40;

elseif GetCashM == 3 && SBal >=100

MonOut = 5 ;

fprintf(' %d 20$ bills were dispensed\n',MonOut)

NewSBal = SBal - 100;

elseif GetCashM ==4 && SBal >=200

MonOut = 10 ;

fprintf(' %d 20$ bills were dispensed',MonOut)

NewSBal = SBal - 200;

else

fprintf('not enough funds in savings account\n')

break;

end

if Mainmenu ==2

checAcct= menu('From which account','checking','Saving');

if checAcct == 1

fprintf('Your Checking Account balance is %d$\n', CBal)

elseif checAcct ==2

fprintf('Your Savings Account balance is %d$\n', SBal)

end

end

if Mainmenu == 3

NewCBal = CBal;

NewSBal = SBal;

fprintf('New Cecking account balance is %d\n',NewCBal)

fprintf('New Saving account balance is %d\n',NewSBal)

i = i+3;

end

if Mainmenu ==0

fprintf('warning')

i = i +1;

end

end

end

[Walter Roberson]

After your tests for specific Acct values you want plain if not elseif

[mat geek]

ok, I will try to do that. thank you.

[mat geek]

Thenk you for the help. It is working now just fine.