How to turn a large array into multiple smaller arrays

Hi,

I have an array that has 31 rows and 1518 columns. I'm trying to figure out a quick way to turn that array into 759 arrays that are 31 rows and 2 columns. I want to take the first two columns, then the next two columns, etc. I was wondering this there was a way to do this in a loop, but was unsure if you could create and name new arrays in a loop. Any help would be much appreciated!

Thanks,

Lori

[Oleg Komarov]

Please, do not post duplicate questions. Also, do not create incremental variables by splitting your array. It's a design suicide and bad programming practice.

Answer 1

[Wayne King]

I think you want to store the separate matrices in a cell array rather than having 759 separate matrices, right? I mean you can always just access each of the 31x2 matrices from the cell array

 X = randn(31,1518);
 k = 1;
 for nn = 1:2:1518-1
    Y{k} = X(:,nn:nn+1);
    k = k+1;
 end

Now you can access each of the 31x2 matrices as

Y{1}, Y{2}, etc.

[k]

Hi! Is there a way to add to this loop a way for the program to plot every Y{} matrix, potentially in the same layout via tiledlayout()?

Answer 2

[Azzi Abdelmalek]

 A=rand(31,1518);  %example
 B=reshape(A,31,2,1518/2)
for k=1: 1518/2
    out.(sprintf('A%d',k))=B(:,:,k)
end

the first array is

   out.A1,

thee second is

   out.A2 ,

the last

   out.A759

Answer 3

[Andrei Bobrov]

out1 = reshape(yourmatrix,size(yourmatrix,1),2,[]);

or

out2 = mat2cell(yourmatrix,size(yourmatrix,1),2*ones(size(yourmatrix,2)/2,1));