Problem plotting bode for a 2nd order system
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François Blas
le 13 Mai 2019
Modifié(e) : Jan
le 15 Mai 2019
Hi, I'm getting started with simulink, I tried to simulate a 2nd order mass spring system but the bode plot seems odd :

K1 = 50
K=1/m1 = 1
I don't know which linear analysis point to choose
This system should have a resonance iif c1 < 1/sqrt(2)
If I choose open loop output, then bode NEVER shows a resonance no matter what c1 is.
If i choose output measurement, bode shows me a resonance if c1 < 9 (instead of 1/sqrt(2))
So, which analysis point should i use ?
4 commentaires
Jan
le 15 Mai 2019
Modifié(e) : Jan
le 15 Mai 2019
@François Blas: Again: Please stop bumping your question by posting pseudo-answers. This behavior is not liked in this forum and it is possible, that you question is ignored in consequence.
Counting the time since you've asked your question looks taunting.
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Sulaymon Eshkabilov
le 13 Mai 2019
Modifié(e) : Sulaymon Eshkabilov
le 13 Mai 2019
Hi Francois,
I have tested and simulated your example and it works as it has to w.r.t. the values of M1, K1, C1. In fact, for your data: K1 = 50, M1 =1, C1 = 2 (e.g). The resonant occurs at the frequency of sqrt(50/1) (approximately 7 Hz) and not @ sqrt(2) as you were anticipating. The selection of output measurement, is the right one. Here is my tested Simulink model. It is in fact correct that the resonant occurs at sqrt(50) => 7Hz that can be seen from the TF of SMD: 1/ (M1s^2+C1s+K1) ==> resonant freq: = sqrt(K1/M1).
Good luck.
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