I want to label each three bars as p1, p2 and p3 for all at the base as the pic attached.. i appreciate any help someone can provide.

2 commentaires

Adam Danz
Adam Danz le 16 Mai 2019
Wouldn't a legend defining the colors make more sense?
Ali Ali
Ali Ali le 16 Mai 2019
you are right.. but i'll manopolate with the colors later.. so it will not be fixed as it now.

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 Réponse acceptée

Adam Danz
Adam Danz le 16 Mai 2019
Modifié(e) : Adam Danz le 10 Déc 2021

0 votes

Here's how to locate the center of each grouped bar and label them.
Starting in Matlab R2019B, the center of each bar is stored in
h = bar(___);
h.XEndPoints % x centers
h.YEndPoints % y endpoints
Prior to Matlab R2019B, you can use an undocumented property "XOffset". This was developed and tested in r2019a.
xCnt are the bar centers.
% Generate grouped bar plot
figure()
v = randi(20,12,3);
h = bar(v,.8);
% Get group centers
xCnt = get(h(1),'XData') + cell2mat(get(h,'XOffset')); % XOffset is undocumented!
% Create Tick Labels
xLab = repmat({'p1','p2','p3'},1,numel(xCnt)/3);
% Set individual ticks
set(gca, 'XTick', sort(xCnt(:)), 'XTickLabel', xLab)
Alternatively, you could rotate the x tick labels
set(gca, 'XTick', sort(xCnt(:)), 'XTickLabel', xLab, 'xticklabelrotation', 90)
% Or use xtickangle(): https://www.mathworks.com/help/matlab/ref/xtickangle.html
The best solution would be to use a legend
legend(h,{'p1','p2','p3'})

8 commentaires

Sulaymon Eshkabilov
Sulaymon Eshkabilov le 16 Mai 2019
Modifié(e) : Sulaymon Eshkabilov le 16 Mai 2019
My understanding of the problem was just to set colors on each bar that is all. If this is the case, then you need to fix a color in your bar charts as shown above. Otherwise, all done = well, already!
Ali Ali
Ali Ali le 17 Mai 2019
Adam Danz this is just perfect bro.
Adam Danz
Adam Danz le 17 Mai 2019
Glad I could help. I recommend writing a comment in your code noting that xoffset is an undocumented property in case it's ever removed in the future.
Ali Ali
Ali Ali le 18 Mai 2019
thank you for this notiation Adam.. I have another question about the possiblility of making the labels at the base mix of p1,p2,p3 and the iterations numbers..?
Adam Danz
Adam Danz le 18 Mai 2019
Modifié(e) : Adam Danz le 18 Mai 2019
Is the iterations number the group number? Something like this below?
p1 i1
p2 i1
p3 i1
p1 i2
p2 i2
p3 i2
If so, give this a shot.
% Create Tick Labels
xLab = repmat({'p1 i','p2 i','p3 i'},1,numel(xCnt)/3);
xLab = strrep(xLab,'i',strsplit(num2str(repelem(1:size(v,1),1,size(v,2)))));
190517 224750-Figure 1.jpg
Ali Ali
Ali Ali le 19 Mai 2019
like below if you can Adam
Adam Danz
Adam Danz le 19 Mai 2019
Modifié(e) : Adam Danz le 19 Mai 2019
% xLab are the labels for each individual bar. The pattern you want is the following:
% for every odd triplet, you want [nothing, #, nothing]
% and for every even triplet you want [p#, p#, p#].
% We already have the p# labels so we just need to alter the odd number groups.
% Step 1) Identify the odd number groups.
isOdd = repmat(logical([1,1,1,0,0,0]),1,length(xLab)/6);
% Step 2) Create new labels
newLabs = strsplit(sprintf('| |%d| |', 1:2:length(xLab)/3),'|');
newLabs(cellfun(@isempty, newLabs)) = [];
% Step 3) replace the p# labels for odd groups with [nothing, #, nothing]
xLab(isOdd) = newLabs;
% Step 4) assing newlabels to plot
set(gca, 'XTick', sort(xCnt(:)), 'XTickLabel', xLab, 'xticklabelrotation', 90)
Ali Ali
Ali Ali le 20 Mai 2019
thank you a lot Adam.. this is realy helped me.

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Plus de réponses (2)

Sulaymon Eshkabilov
Sulaymon Eshkabilov le 16 Mai 2019

0 votes

Hi Ali,
Here is a simple solution to your problem:
A= randi([15, 25], 13, 3); % Insert your data here
H = bar(A); shg
H(1).FaceColor='g';
H(2).FaceColor='r';
H(3).FaceColor='b';
Good luck.

1 commentaire

Ali Ali
Ali Ali le 17 Mai 2019
Sulaymon Eshkabilov i think you did not get my point.. anyway thank you for your help.

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Sergio Yanez-Pagans
Sergio Yanez-Pagans le 21 Août 2021

0 votes

1 commentaire

Adam Danz
Adam Danz le 21 Août 2021
Cool function, but how does that address the question of how to label the bar groups?

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