i need help to understand the steps of this code

2 vues (au cours des 30 derniers jours)
Bekhtaoui Abdelhakim
Bekhtaoui Abdelhakim le 28 Mai 2019
Commenté : Image Analyst le 29 Mai 2019
hi everyone please can someone explain to me the steps of this program ?
its a coherence filter program
thanks for helping
%%%
function myCEDnew( )
myalpha = 0.001; sigma=0.7; T = 15; rho = 4; C= 1;
im = imread('../images/2.png');
[numrow, numcol] = size(im);
imorig = im;
stepT=0.15;
t = 0;
im=double(im);
while (t < (T-0.001))
t = t + stepT;
%% 1 gaussian K_sigma
limitX=-ceil(2*sigma):ceil(2*sigma);
kSigma = exp(-(limitX.^2/(2*sigma^2)));
kSigma = kSigma/sum(kSigma(:));
usigma=imfilter(imfilter(im,(kSigma'), 'same' ,'replicate'),kSigma, 'same' ,'replicate');
%% Gradient
[uy,ux]=gradient(usigma);
%% 3 gaussian K_rho
limitXJ=-ceil(3*rho):ceil(3*rho);
kSigmaJ = exp(-(limitXJ.^2/(2*rho^2)));
kSigmaJ = kSigmaJ/sum(kSigmaJ(:));
Jxx = imfilter(imfilter((ux.^2),(kSigmaJ'), 'same' ,'replicate'),kSigmaJ, 'same' ,'replicate');
Jxy = imfilter(imfilter((ux.*uy),(kSigmaJ'), 'same' ,'replicate'),kSigmaJ, 'same' ,'replicate');
Jyy = imfilter(imfilter((uy.^2),(kSigmaJ'), 'same' ,'replicate'),kSigmaJ, 'same' ,'replicate');
%% Principal axis transformation
% Eigenvectors of J, v1 and v2
v2x = zeros(numrow, numcol);
v2y = zeros(numrow, numcol);
lambda1 = zeros(numrow, numcol);
lambda2 = zeros(numrow, numcol);
for i=1:numrow
for j=1:numcol
pixel = [Jxx(i,j), Jxy(i,j); Jxy(i,j), Jyy(i,j)];
[pixelV, pixelD] = eig(pixel);
v2x(i,j) = pixelV(1,2);
v2y(i,j) = pixelV(2,2);
lambda1(i,j) = pixelD(1,1);
lambda2(i,j) = pixelD(2,2);
if((v2x(i,j)^2)+(v2y(i,j)^2)==0)
abcd=0;
else
v2x(i,j) = v2x(i,j)/(sqrt((v2x(i,j)^2)+(v2y(i,j)^2)));
v2y(i,j) = v2y(i,j)/(sqrt((v2x(i,j)^2)+(v2y(i,j)^2)));
end;
end;
end;
v1x = -v2y;
v1y = v2x;
%% Calculation of diffusion matrix
di=(lambda1-lambda2);
lambda1 = myalpha + (1 - myalpha)*exp(-C./(di).^(2));
lambda2 = myalpha;
Dxx = lambda1.*v1x.^2 + lambda2.*v2x.^2;
Dxy = lambda1.*v1x.*v1y + lambda2.*v2x.*v2y;
Dyy = lambda1.*v1y.^2 + lambda2.*v2y.^2;
%% Non negativity discretization scheme referred from http://citeseer.ist.psu.edu/viewdoc/download;jsessionid=16CCEAD1A72E6A1CC960DF99795D62B7?doi=10.1.1.21.632&rep=rep1&type=pdf
im=non_negativity_discretization(im,Dxx,Dxy,Dyy,stepT);
end;
%% output
figure(1);
subplot(1, 2, 1);
imagesc(imorig);
title('Original image');
colormap('Gray');
daspect ([1 1 1]);
subplot(1, 2, 2);
imagesc(im);
title('Coherence Enhancing Diffusion Filtering');
colormap('Gray');
daspect ([1 1 1]);
figure(2);
subplot(1, 2, 1);
imagesc(imorig);
title('Original image');
colormap('Gray');
daspect ([1 1 1]);
subplot(1, 2, 2);
imagesc(atan2(double(uy), double(ux)));
title('Orientation of smooth gradient');
colormap('Gray');
daspect ([1 1 1]);
imwrite((uint8(im)), '../images/2CED.png');
end
function im=non_negativity_discretization(im,Dxx,Dxy,Dyy,stepT)
% Make positive and negative indices
[numrow,numcol] = size(im);
px = [2:numrow,numrow]; nx = [1,1:numrow-1];
py = [2:numcol,numcol]; ny = [1,1:numcol-1];
% In literature a,b and c are used as variables
a=Dxx;b=Dxy;c=Dyy;
% Stencil Weights
wbR1 = (0.25)*((abs(b(nx, py))-b(nx,py)) + (abs(b)-b));
wtM2 = (0.5)*( (c(:, py)+c) -(abs(b(:,py))+abs(b)));
wbL3 = (0.25)*((abs(b(px, py))+b(px,py)) + (abs(b)+b));
wmR4 = (0.5)*( (a(nx,: )+a) -(abs(b(nx,:))+abs(b)));
wmL6 = (0.5)*( (a(px,: )+a) -(abs(b(px,:))+abs(b)));
wtR7 = (0.25)*((abs(b(nx, ny))+b(nx,ny)) + (abs(b)+b));
wmB8 = (0.5)*( (c(:, ny)+c) -(abs(b(:,ny))+abs(b)));
wtL9 = (0.25)*((abs(b(px, ny))-b(px,ny)) + (abs(b)-b));
im= im+stepT*(wbR1.*(im(nx,py) -im(:,:))+wtM2.*(im(:, py) -im(:,:))+wbL3.*(im(px,py) -im(:,:))+wmR4.*(im(nx,:) -im(:,:))+ ...
wmL6.*(im(px,:) -im(:,:))+ wtR7.*(im(nx,ny) -im(:,:))+ wmB8.*(im(:, ny) -im(:,:))+ wtL9.*(im(px,ny) -im(:,:)));
end
  1 commentaire
Image Analyst
Image Analyst le 29 Mai 2019
I doubt any of us can/would, but the authors probably would. Have you asked them?

Connectez-vous pour commenter.

Réponses (0)

Catégories

En savoir plus sur Geometric Transformation and Image Registration dans Help Center et File Exchange

Produits

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by