Sorting a structure using Matlab2018

2 vues (au cours des 30 derniers jours)
Shamsuddeen Abdullahi
Shamsuddeen Abdullahi le 29 Mai 2019
Réponse apportée : Jan le 29 Mai 2019
Hi
I want to sort this structure in descensind order using MATLAB 2018:
ten.cat=[7,2,4,1].
I used the following commands but it is still not sorted:
pp_1=ten;
TT = struct2table(pp_1) % convert to tables
gg=sortrows(TT,'cat') % sort
sortedpp_1 = table2struct(gg) % convert the table back to structure.
please, help
  3 commentaires
Guillaume
Guillaume le 29 Mai 2019
@Jan, this should go as an answer as I see no way of improving on that with the information given.
@shamsuddeen, there's never any need to convert a structure to anything in order to operate on it. Certainly, converting a structure into a table and back is a complete waste of time for your purpose. In this case, the fact that ten is a structure is completely irrelevant anyway, you're not sorting a structure, but just one field of a scalar structure which is the same as any non-structure variable.
Shamsuddeen Abdullahi
Shamsuddeen Abdullahi le 29 Mai 2019
Thank u. it works

Connectez-vous pour commenter.

Réponse acceptée

Jan
Jan le 29 Mai 2019
ten.cat = [7,2,4,1];
ten.cat = sort(ten.cat)

Plus de réponses (1)

Simon Mählkvist
Simon Mählkvist le 29 Mai 2019
Modifié(e) : Simon Mählkvist le 29 Mai 2019
Hi,
Adjusting:
ten.cat=[7,2,4,1]
to:
ten.cat=[7;2;4;1]
gives what I think is the sought after results.

Catégories

En savoir plus sur Shifting and Sorting Matrices dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by