Generated code that mulitples previous number

1 vue (au cours des 30 derniers jours)
Tino
Tino le 30 Mai 2019
Commenté : Tino le 30 Mai 2019
Hello I want to compute a value assuming Xo = 1
using the formular X = e * (p) . ^ ( e - 1) * X
for first X = e * (p) . ^ ( e - 1) * Xo
Second X = e * (p) . ^ ( e - 1) * X1
Third X = e * (p).^(e - 1) * X2
fourth X = e * (p). ^ (e - 1) * X3
it can be simplified
X0 = 1
X1 = e * (p) . ^ ( e - 1) * Xo
X2 = e * (p) . ^ ( e - 1) * X1
X3 = e * (p) . ^ ( e - 1) * X2
X4 = e * (p) . ^ ( e - 1) * X3
Can anyone assist me in generating this code
Thanks in advance
Regards
Tino

Réponse acceptée

Stephen23
Stephen23 le 30 Mai 2019
Modifié(e) : Stephen23 le 30 Mai 2019
I specified:
e = 1.2;
p = 2.3;
and then your code produces:
X0 =
1
X1 =
1.4175
X2 =
2.0093
X3 =
2.8483
X4 =
4.0375
Simpler MATLAB code using power:
>> (e*p.^(e-1)).^(0:4)
ans =
1 1.4175 2.0093 2.8483 4.0375
or cumprod (as Steven Lord suggested):
>> cumprod(e*p.^(e-1)*ones(1,4))
ans =
1.4175 2.0093 2.8483 4.0375
  7 commentaires
Stephen23
Stephen23 le 30 Mai 2019
e = 1.2;
p = [3,4;5,6];
N = 5;
C = cell(1,N);
C{1} = 1;
for k = 2:N
C{k} = e*p.^(e-1) * C{k-1};
end
Giving:
>> C{:}
ans = 1
ans =
1.4949 1.5834
1.6557 1.7172
ans =
4.8563 5.0860
5.3181 5.5703
ans =
15.680 16.423
17.172 17.986
ans =
50.631 53.029
55.449 58.076
Tino
Tino le 30 Mai 2019
thanks Stephen. I appreciate

Connectez-vous pour commenter.

Plus de réponses (1)

Steven Lord
Steven Lord le 30 Mai 2019
Use the cumprod function. [Don't make individually numbered variables, store them as elements of one vector.]
  1 commentaire
Tino
Tino le 30 Mai 2019
Thanks Steve
I have done this but not working
e = 0.92;
nnn = e * P.^(e - 1);
for j = 1 : kol
X{j} = cumprod(nnn);
end
But not working how do I go about it

Connectez-vous pour commenter.

Catégories

En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange

Tags

Produits


Version

R2019a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by