write a matlab code that plots the following piece wise function f(t) = ( 3t^2 +5 t>0)and f(t)=(-e^t + 5t <0 )

4 commentaires

Rik
Rik le 3 Juin 2019
Seems like a clear description of your homework. What is your question?
madhan ravi
madhan ravi le 3 Juin 2019
What have you tried so far?
JONATHAN KATHUZA
JONATHAN KATHUZA le 3 Juin 2019
Modifié(e) : Rik le 3 Juin 2019
Edit Rik: copied code from attached file to comment text.
%%ploting a piecewise function
%created by Jonathan kathuza, Promise Kalonga,Christina Mkanyoza,Samuel Mboma
%Fatsani Tamandikani,Wonderful Lijoni Duwa
%02nd June 2019;
a=input('enter starting point \n');
b=input('enter end point \n');
t=a:0.01:b;
y1= -exp(t)+5;
y2=3*(t.^2)+5;
if a<0&&b<0
plot(t,y1)
xlabel('t');
ylabel('y');
elseif a>=0&&b>=0
plot(t,y2)
xlabel('t');
ylabel('y');
elseif a<0&&b>=0
plot(t,y1,'r-',t,y2,'g-')
legend('-exp(t)+5','3*(t.^2)+5;')
else
disp('invalid inputs')
end
darova
darova le 3 Juin 2019
Is there something we can help you? What is the question?

Connectez-vous pour commenter.

Réponses (1)

Rik
Rik le 3 Juin 2019

0 votes

That is a good idea of solving your problem. There is one thing you're forgetting in your logic: to trim the parts you don't need in the third case. The solution to that is logical indexing, which is a good idea in the first place.
There is some code missing (because I'm not making your homework for you), but these parts should get you where you need to be.
a=-3;b=4;
if a>=b
error('invalid inputs')
end
t=a:0.01:b;
L=___
y=zeros(size(t));
y(~L)= -exp(t(~L))+5;
y(L)=3*(t(L).^2)+5;
But there is an even better solution: you can put your piecewise function in a single anonymous function and let fplot handle your problems. I'm using different conditions and functions as an example here, but you shouldn't have any trouble adapting it to your own problem.
f1=@(t)-exp(t);%function 1
f2=@(t) cos(t*5);%function 2
cond=@(t) sin(t*15)>0;%when this condition is true, set f2 to 0
f=@(t) f1(t).*cond(t) + f2(t).*~cond(t);
fplot(f,[a b])

Commenté :

le 3 Juin 2019

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by