hi every one , how can i do a for cycle with diffrent vector length , thank you
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
clear all
clc
X=rand(17,1)
Y=rand(31,1)
Z=rand(28,1)
K=rand(31,1)
n=31
for i=1:n
A=[X(:,n) , Y(:,n) ,Z(:,n) ,K(:,n)];
AT{1,n}= inv(A{1,n}'*A{1,n})*A{1,n}';
end
2 commentaires
Rik
le 5 Juin 2019
What do you mean? You aren't using standard Matlab terms, nor are you describing any errors, nor what your goal is. Have a read here and here. It will greatly improve your chances of getting an answer.
I do notice that your vectors have different lengths, yet you want to put them together? What should A look like when n is 18? Should it be a 3-element vector?
And why are you selecting all rows and non-existant later columns for n>1? And why are you using curly braces on a non-cell array?
Réponse acceptée
Rik
le 6 Juin 2019
You can put them in a cell array and let cell2mat handle the removal of empty elements. I have no clue what you want to do with that variable inside your loop, so I replaced it with sum to have a proof of principle. (also, no need for clear all)
X=rand(17,1);
Y=rand(31,1);
Z=rand(28,1);
K=rand(31,1);
A=cell(numel(X),4);
A(1:numel(X),1)=num2cell(X);
A(1:numel(Y),2)=num2cell(Y);
A(1:numel(Z),3)=num2cell(Z);
A(1:numel(K),4)=num2cell(K);
AT=zeros(1,size(A,1));
for n=1:size(A,1)
B=A(n,:);B=cell2mat(B);
AT(n)= sum(B);
end
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!