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How to draw a rotated ellipse without any toolbox?

26 vues (au cours des 30 derniers jours)
ManKit Tse
ManKit Tse le 28 Août 2012
Commenté : Vivek Bhartiya le 30 Mar 2020
I need to draw rotated ellipse on a Gaussian distribution plot by surf. I am using a student version MATLAB. Can i still draw a ellipse center at estimated value without any toolbox that required money to buy. I search on internet somebody write ellipse function and allow to download. Are they work well on surf plot.

Réponse acceptée

Babak
Babak le 28 Août 2012
Modifié(e) : Babak le 28 Août 2012
t = linspace(0,2*pi,1000);
theta0 = pi/6;
a=2;
b=1;
x = a*sin(t+theta0);
y = b*cos(t);
plot(x,y)
axis equal
  3 commentaires
Image Analyst
Image Analyst le 2 Sep 2012
Well yeah, because if a or b is really close to zero, the width is really close to zero and the ellipse is essentially almost a line. And a line has to lie along the raster lines on your monitor. The line can be on line 1 or on line 2. You can't have pixels going across the screen at line 1, line 1.01, line 1.02, etc. up to line 1.88 or whatever. It's got to be just on line 1 or on line 2, not on fractional lines. For further reading: http://en.wikipedia.org/wiki/Jaggies
Gabriel Hernandez
Gabriel Hernandez le 9 Déc 2019
Modifié(e) : Gabriel Hernandez le 9 Déc 2019
This code did not work for me. The answer posted below is much more accurate.

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Plus de réponses (1)

Oleksii Sidorov
Oleksii Sidorov le 26 Fév 2018
My version with general parametric equation of rotated ellipse, where 'theta' is angle of CCW rotation from X axis (center at (x0, y0))
t = linspace(0,2*pi,100);
theta = deg2rad(105);
a=2;
b=1;
x0 = 0.15;
y0 = 0.30;
x = x0 + a*cos(t)*cos(theta) - b*sin(t)*sin(theta);
y = y0 + b*sin(t)*cos(theta) + a*cos(t)*sin(theta);
figure;
plot(x,y);
axis equal;
  2 commentaires
Gabriel Hernandez
Gabriel Hernandez le 9 Déc 2019
Your code worked perfectly for me, much better than the one from the accepted answer. Thank you!
Vivek Bhartiya
Vivek Bhartiya le 30 Mar 2020
Fantastic work. It was quite hard to find a functional code.

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